oj.uz

답안 #119881

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
119881 2019-06-22T14:31:52 Z tutis Trapezi (COI17_trapezi) C++17
23 / 100
 500 ms 27436 KB 
/*input
3
.000000
...000000
.....000000
.....0.....
...000...
.00000.

*/
#pragma GCC optimize ("O3")
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double ld;
struct grupe
{
	int x, y, z;
	bool reikia = false;
};
vector<grupe>xx;
vector<char>col;
unordered_set<bitset<54>>M;
bool ieskom(bitset<54>x)
{
	if (x.count() == 0)
		return true;
	if (M.count(x))
		return false;
	for (int i = 0; i < (int)xx.size(); i++)
	{
		if (x[xx[i].x] && x[xx[i].y] && x[xx[i].z])
		{
			x[xx[i].x] = false;
			x[xx[i].y] = false;
			x[xx[i].z] = false;
			xx[i].reikia = true;
			if (ieskom(x))
			{
				return true;
			}
			xx[i].reikia = false;
			x[xx[i].x] = true;
			x[xx[i].y] = true;
			x[xx[i].z] = true;
		}
	}
	M.insert(x);
	return false;
}
int main()
{
	int n;
	cin >> n;
	string s[2 * n];
	for (int i = 0; i < 2 * n; i++)
		cin >> s[i];
	vector<int>id[2 * n];
	int timer = 0;
	for (int i = 0; i < 2 * n; i++)
		for (char c : s[i])
		{
			id[i].push_back(timer++);
			col.push_back(c);
		}
	vector<int>adj[timer];
	for (int i = 0; i < 2 * n; i++)
	{
		for (int t = 0; t + 1 < (int)id[i].size(); t++)
		{
			int x = id[i][t];
			int y = id[i][t + 1];
			adj[x].push_back(y);
			adj[y].push_back(x);
		}
	}
	for (int i = 0; i <= n - 2; i++)
	{
		for (int t = 0; t < (int)id[i].size(); t += 2)
		{
			int x = id[i][t];
			int y = id[i + 1][t + 1];
			adj[x].push_back(y);
			adj[y].push_back(x);
		}
	}
	for (int t = 0; t < (int)id[n - 1].size(); t += 2)
	{
		int x = id[n - 1][t];
		int y = id[n][t];
		adj[x].push_back(y);
		adj[y].push_back(x);
	}
	for (int i = n + 1; i < 2 * n; i++)
	{
		for (int t = 0; t < (int)id[i].size(); t += 2)
		{
			int x = id[i][t];
			int y = id[i - 1][t + 1];
			adj[x].push_back(y);
			adj[y].push_back(x);
		}
	}
	for (int i = 0; i < timer; i++)
	{
		for (int j : adj[i])
		{
			for (int k : adj[i])
			{
				if (j < k)
				{
					grupe a;
					a.x = i;
					a.y = j;
					a.z = k;
					xx.push_back(a);
				}
			}
		}
	}
	bitset<54>x;
	for (int i = 0; i < 2 * n; i++)
	{
		for (int t = 0; t < (int)id[i].size(); t++)
		{
			if (s[i][t] == '0')
				x[id[i][t]] = true;
		}
	}
	if (ieskom(x))
	{
		for (grupe a : xx)
		{
			if (a.reikia == false)
				continue;
			set<int>aplink;
			for (int i : {a.x, a.y, a.z})
				for (int j : adj[i])
					aplink.insert(j);
			for (int i : {a.x, a.y, a.z})
				aplink.erase(i);
			set<char>cols;
			for (int i : aplink)
				cols.insert(col[i]);
			for (char x = '1'; x <= '6'; x++)
				if (cols.count(x) == 0)
				{
					col[a.x] = x;
					col[a.y] = x;
					col[a.z] = x;
				}
		}
		for (int i = 0; i < 2 * n; i++)
		{
			for (int t = 0; t < (int)id[i].size(); t++)
			{
				cout << col[id[i][t]];
			}
			cout << endl;
		}
	}
	else
		cout << "nemoguce\n";
}

Subtask #1
6.0 / 6.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 384 KB Output is correct
2 Correct 2 ms 384 KB Output is correct

Subtask #2
17.0 / 17.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3 ms 384 KB Output is correct
2 Correct 2 ms 384 KB Output is correct
3 Correct 2 ms 384 KB Output is correct
4 Correct 2 ms 384 KB Output is correct

Subtask #3
0 / 18.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1070 ms 25616 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #4
0 / 22.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1067 ms 27436 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #5
0 / 37.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1070 ms 24940 KB Time limit exceeded
2 Halted 0 ms 0 KB -