#include <bits/stdc++.h>
using namespace std;
#define endl "\n"
#define int long long
using ull=unsigned long long;
using ll=long long;
using pii=pair<int,int>;
const int dx[4] = {1,0,-1,0}, dy[4] = {0,1,0,-1};
const int mod=1e9+7;
#define OVL(x,s) for(auto y:x) cout<<y<<s; cout<<"\n";
template <typename T> istream& operator>>(istream& is, vector<T> &a) {
copy_n(istream_iterator<T>(is), a.size(), a.begin()); return is;}
#ifdef IOI
template<typename A, typename B> ostream& operator<<(ostream &os, const pair<A, B> &p) { return os << '(' << p.first << ", " << p.second << ')'; }
template<typename T_container, typename T = typename enable_if<!is_same<T_container, string>::value, typename T_container::value_type>::type> ostream& operator<<(ostream &os, const T_container &v) { os << '{'; string sep; for (const T &x : v) os << sep << x, sep = ", "; return os << '}'; }
void dbg_out() { cout << endl; }
template<typename Head, typename... Tail> void dbg_out(Head H, Tail... T) { cout << ' ' << H; dbg_out(T...); }
#define dbg(...) cout << "(" << #__VA_ARGS__ << "):", dbg_out(__VA_ARGS__);
#else
#define dbg(...) 1337;
#endif
#define pb push_back
#define F first
#define S second
#define all(v) v.begin(),v.end()
vector<vector<int>> merge(vector<vector<int>>& intervals) {
sort(intervals.begin(), intervals.end());
vector<vector<int>> merged;
for (auto interval : intervals) {
// if the list of merged intervals is empty or if the current
// interval does not overlap with the previous, simply append it.
if (merged.empty() || merged.back()[1] < interval[0]) {
merged.push_back(interval);
}
// otherwise, there is overlap, so we merge the current and previous
// intervals.
else {
merged.back()[1] = max(merged.back()[1], interval[1]);
}
}
return merged;
}
signed main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
int n,a,b;
cin>>n>>a>>b;
vector<vector<int>> v;
for(int i = 0;i<n;i++){
int l,r;
cin>>l>>r;
l<<=1;
r<<=1;
l%=a;
r%=a;
if(l<=r){
v.pb({l,r});
}else{
v.pb({l,a-1});
v.pb({0,r});
}
}
vector<vector<int>> ans = merge(v);
int sum = 0;
for(int i = 0;i<ans.size();i++){
int t = ans[i][1]-ans[i][0]+1;
sum += (t+1)/2;
}
cout<<sum<<endl;
}
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