제출 #1193651

#제출 시각아이디문제언어결과실행 시간메모리
1193651pinbuCat Exercise (JOI23_ho_t4)C++20
100 / 100
194 ms45832 KiB
#include <bits/stdc++.h> using namespace std; const int N = 200005, L = 17; int n, p[N], po[N]; vector<int> adj[N]; int h[N], up[N][L + 1]; void DFS(int u, int pa) { for (int v: adj[u]) { if (v == pa) { continue; } h[v] = h[u] + 1; up[v][0] = u; for (int k = 1; k <= L; k++) { up[v][k] = up[up[v][k - 1]][k - 1]; } DFS(v, u); } } int LCA(int u, int v) { if (h[u] < h[v]) swap(u, v); int d = h[u] - h[v]; for (int k = 0; k <= L; k++) { if ((d >> k) & 1) { u = up[u][k]; } } if (u == v) { return u; } for (int k = L; k >= 0; k--) { if (up[u][k] ^ up[v][k]) { u = up[u][k]; v = up[v][k]; } } return up[u][0]; } int dist(int u, int v) { return h[u] + h[v] - 2 * h[LCA(u, v)]; } int root[N]; int find(int u) { return u ^ root[u] ? root[u] = find(root[u]) : u; } long long dp[N]; void solve(void) { cin >> n; for (int i = 1; i <= n; i++) { cin >> p[i]; po[p[i]] = i; } for (int i = 1, u, v; i < n; i++) { cin >> u >> v; adj[u].emplace_back(v); adj[v].emplace_back(u); } h[1] = 0; DFS(1, 1); iota(root + 1, root + 1 + n, 1); for (int num = 1; num <= n; num++) { int u = po[num]; for (int v: adj[u]) { if (p[v] < p[u]) { int rv = find(v); dp[u] = max(dp[u], dp[rv] + dist(u, rv)); root[rv] = u; } } } cout << dp[po[n]]; } signed main(void) { ios::sync_with_stdio(false); cin.tie(nullptr); solve(); return 0; }
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