제출 #1192921

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1192921		ildar1	식물 비교 (IOI20_plants)	C++20	0 / 100	37 ms	6468 KiB

plants

#include <iostream>
#include <vector>
#include <cassert>
#include <stack>

#define MAXN 200001

using namespace std;

int ans[MAXN];  //ans[x] = rank of h[x]
int myr[MAXN];

int next_bigger[MAXN]; //next_bigger[x] = index between x+1 and x+k-1 so that h[bigger[x]]
int prev_bigger[MAXN]; //prev_bigger[x] = index between x-k+1 and x-1 so that h[prev_bigger[x]] is smallest term bigger than it else -1
stack<int> s;


int n;

int h;

bool comparePairs(const pair<int,int> &p1, const pair<int,int> &p2) {
	return true;
}

struct Seg{

	pair<int,int> tree[2*MAXN];
	int lazy[MAXN];

	void make() {
		for (int i=0; i<n; i++) {
			tree[i+n].first = myr[i];
			tree[i+n].second = i;
		}
		for (int i=n-1; i>0; i--) {
			tree[i] = min(tree[i<<1], tree[i<<1|1]);
			if (tree[i<<1].first==tree[i<<1|1].first) {
				tree[i].second = max(tree[i<<1|1].second, tree[i<<1].second);

			}
		}
	}

	void apply(int p, int val) {
		tree[p].first += val;
		if (p<n) lazy[p] += val;
	} 

	void build(int p) {
		while (p>1) {
			p>>=1;
			int x = tree[p<<1].first;
			int y = tree[p<<1|1].first;
			if (x<=y) {
				tree[p].first = x + lazy[p];
				tree[p].second = (x<y) ? tree[p<<1].second: max(tree[p<<1|1].second, tree[p<<1].second);
			} else {
				tree[p].first = y+ lazy[p];
				tree[p].second = tree[p<<1|1].second;
			}
		}
	}

	void push(int p) {
		for (int i=h; i>0; i--) {
			int j = p>>i;
			if (lazy[j] != 0) {
				apply(j<<1, lazy[j]);
				apply(j<<1|1, lazy[j]);
				lazy[j] = 0;
			}
		}
	}

	void increm(int l, int r, int val) {
		l+=n;
		r+=n;
		int l0 = l;
		int r0 = r;
		for (; l<r; l>>=1, r>>=1) {
			if (l&1) apply(l++, val);
			if (r&1) apply(--r, val);
		}
		build(l0);
		build(r0-1);
	}

	pair<int, int> query(int l, int r) {
		l+=n;
		r+=n;
		push(l);
		push(r-1);
		pair<int,int> res = {2e9, -1};
		for (; l<r; l>>=1, r>>=1) {
			if (l&1) {
				int tmp3 = res.first;
				int tmp2 = res.second;
				res = min(res, tree[l]);
				if (tmp3==tree[l].first) res.second = max(tmp2, tree[l].second);
				l++;
			} 
			if (r&1) {
				int tmp3 = res.first;
				int tmp2 = res.second;
				r--;
				res = min(res, tree[r]);
				if (tmp3==tree[r].first) res.second = max(tmp2, tree[r].second);
			} 
		}
		return res;
	}

} seg;

void init(int k, vector<int> r) {
	n = r.size();
	h = 31 - __builtin_clz(n);

	for (int i=0; i<n; i++) myr[i] = r[i];

	seg.make();

	//find the first zero;

	/* pair<int, int> first = seg.query(0, n);
	int ind = first.second;
	if (ind<k-1) {
		pair<int, int> sec = seg.query(n-k+ind+1, n);
		if (sec.first==0) {
			while (true) {
				pair<int, int> ano = seg.query(ind+1, n);
				if (ano.second - ind>k-1) {
					ind = ano.second;
					break;
				}
				ind = ano.second;
			}
		}
	} */

	int ind=seg.query(0,n).second;

	for (int m=0; m<n; m++) {

		/* pair<int, int> first = seg.query(0, n);
		int ind = first.second;
		if (ind<k-1) {
			pair<int, int> sec = seg.query(n-k+ind+1, n);
			if (sec.first==0) {
				ind = sec.second;
			} 
		} */

		while (true) {
			if (!s.empty()) {
				int tmp = s.top();
				if (tmp>=k-1 && seg.query(tmp-k+1, tmp).first>0) {
					s.pop();
					ind = tmp;
					break;
				} else if (tmp>= k-1) {
					s.push(seg.query(tmp-k+1,tmp).second);
				} else if (tmp<k-1 && seg.query(0, tmp).first>0 && seg.query(n-k+tmp+1,n).first>0) {
					s.pop();
					ind = tmp;
					break;
				} else if (tmp<k-1 && seg.query(0,tmp).first>0) {
					s.push(seg.query(n-k+tmp+1,n).second);
				} else {
					s.push(seg.query(0,tmp).second);
				}
			} else {
				if (ind>=k-1) {
					s.push(seg.query(ind-k+1, ind).second);
				} else if (seg.query(0, ind).first==0) {
					s.push(seg.query(0, ind).second);
				} else {
					s.push(seg.query(0, n).second);
				}

			}
		}

		ans[ind] = n-m;
		if (ind >= k-1) {
			seg.increm(ind-k+1, ind, -1);
		} else {
			seg.increm(0, ind, -1);
			seg.increm(n-k+ind+1, n, -1);
		}
		seg.increm(ind, ind+1, n);


	}
}

int compare_plants(int x, int y) {

	if (ans[x] > ans[y]) {
		return 1;
	} else return -1;
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 14
• Subtask 3: 0 / 13
• Subtask 4: 0 / 17
• Subtask 5: 0 / 11
• Subtask 6: 0 / 15
• Subtask 7: 0 / 25