#include<bits/stdc++.h>
using namespace std;
const int maxn=101;
const int inf=1e9+7;
int v[maxn], dp[maxn][2001]; // dp[id][val][qtd] se eu consigo formar o valor val, com partição dos id primeiros caras, usando qtd grupos
// obs: se a=1, ent posso querer minimizar o numero de partições, usar isso p/ fzr a sub3
signed main(){
ios_base::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr);
int n, a, b; cin >> n >> a >> b;
for(int i=1;i<=n;i++) cin >> v[i];
for(int i=0;i<maxn;i++)
for(int j=0;j<=2000;j++) dp[i][j]=inf;
dp[0][0]=0;
int resp=inf;
for(int i=1;i<=n;i++){
int sum=0;
for(int j=i-1;j>=0;j--){
sum+=v[j+1];
for(int val=0;(val|sum)<=2000;val++) dp[i][(val|sum)]=min(dp[i][(val|sum)],dp[j][val]+1);
}
}
for(int i=2000;i>=0;i--) if(a<=dp[n][i]&&dp[n][i]<=b) resp=i;
cout << resp << endl;
}
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