Submission #1192436

#TimeUsernameProblemLanguageResultExecution timeMemory
1192436lance0Robots (IOI13_robots)C++20
0 / 100
3092 ms131072 KiB
#include <bits/stdc++.h> #include "robots.h" using namespace std; int putaway(int A,int B,int T,int X[],int Y[],int W[],int S[]) { vector<int> x,y; for (int i = 0; i < A; i++) { x.push_back(X[i]); } for (int i = 0; i < B; i++) { y.push_back(Y[i]); } //note: weakest robots should take as much as possible first since size will never affect them sort(x.begin(),x.end()); //but largest robots should take as much as possible to ensure smaller robots have something to grab sort(y.begin(),y.end(), greater<int>()); int w_max = 0, s_max = 0; //combine weight/size requirements into one array for sorting vector<pair<int,int>> ws; for (int i = 0; i < T; i++) { w_max = max(w_max, W[i]); s_max = max(s_max, S[i]); ws.push_back(make_pair(W[i],S[i])); } sort(ws.begin(),ws.end()); //cleaner to do it now than worry about it in binsearch, though slower if (w_max > x[A-1] and s_max > y[B-1]) { return -1; } else { int low = 0, high = T; while(low < high) { int mid = (low + high) / 2; priority_queue<int> pq; int count = 0; // counting toys doable by weak for (int i = 0; i < A; i++) { while (count < T) { if (ws[i].first < x[i]) { pq.push(ws[i].second); } } for (int j = 0; j < mid; j++) { if (!pq.empty()) { pq.pop(); } else { break; } } } for (int i = count; i < T; i++) { pq.push(ws[i].second); } for (int i = 0; i < B; i++) { if (pq.size() == 0) { break; } else { for (int j = 0; j < mid; j++) { if (!pq.empty()) { if (pq.top() >= y[i]) { pq.pop(); } } else { break; } } } } if (pq.size() > 0) { low = mid + 1; } else { high = mid; } } return low; } }
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