제출 #1192304

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1192304		Mousa_Aboubaker	Shortcut (IOI16_shortcut)	C++20	0 / 100	2096 ms	328 KiB

shortcut

#include "shortcut.h"
#include <bits/stdc++.h>
using namespace std;

template <typename T>
using pqg = priority_queue<T, vector<T>, greater<T>>;

long long find_shortcut(int n, vector<int> l, vector<int> d, int C)
{
    int cnt = count_if(d.begin(), d.end(), [&](int x){
        return x > 0;
    });
    vector adj(n + cnt, multiset<pair<int, int>>());
    for(int i = 0; i + 1 < n; i++)
    {
        adj[i].insert({i + 1, l[i]});
        adj[i + 1].insert({i, l[i]});
    }
    for(int i = 0, j = 0; i < n; i++)
    {
        if(d[i] == 0)
            continue;
        adj[i].insert({n + j, d[i]});
        adj[n + j].insert({i, d[i]});
        j++;
    }
    long long mn = 1e18 + 10;
    vector<long long> dis(n + cnt);
    auto bfs = [&](int start) -> void
    {
        pqg<pair<int, long long>> pq;
        dis.assign(n + cnt, 1e18 + 10);
        pq.push({start, 0});
        while(not pq.empty())
        {
            auto [u, c] = pq.top();
            pq.pop();
            
            if(dis[u] <= c)
                continue;
            dis[u] = c;
            for(auto [v, w]: adj[u])
                pq.push({v, c + w});
        }
    };
    for(int i = 0; i < n; i++)
    {
        for(int j = i + 1; j < n; j++)
        {
            adj[i].insert({j, C});
            adj[j].insert({i, C});
            long long mx = 0;
            for(int k = 0; k < n + cnt; k++)
            {
                bfs(k);
                long long s = *max_element(dis.begin(), dis.end());
                if(mx < s)
                    mx = s;
            }
            if(mn > mx)
                mn = mx;
            adj[i].erase(adj[i].find({j, C}));
            adj[j].erase(adj[j].find({i, C}));
        }
    }
    return mn;
}

컴파일 시 표준 에러 (stderr) 메시지

shortcut.h:1:9: warning: #pragma once in main file
    1 | #pragma once
      |         ^~~~
shortcut_c.h:1:9: warning: #pragma once in main file
    1 | #pragma once
      |         ^~~~

• Subtask 1: 0 / 9
• Subtask 2: 0 / 14
• Subtask 3: 0 / 8
• Subtask 4: 0 / 7
• Subtask 5: 0 / 33
• Subtask 6: 0 / 22
• Subtask 7: 0 / 4
• Subtask 8: 0 / 3