Submission #1190653

#	Time	Username	Problem	Language	Result	Execution time	Memory
1190653		Ardelion	Global Warming (CEOI18_glo)	C++20	0 / 100	37 ms	2500 KiB

glo

#include <bits/stdc++.h>
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("O3")
//#pragma GCC target("avx2")

using namespace std;

//#define int          long long
#define ll           long long
#define X            first
#define Y            second
#define lc           (id<<1)
#define rc           (lc|1)
#define mid          ((l+r+1)>>1)
#define pb           push_back
#define lb           lower_bound
#define ub           upper_bound
#define mp           make_pair
#define sep          ' '
#define endl         "\n"
#define migmig       ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define FileIO       freopen("input.txt", "r", stdin); freopen("output.txt", "w", stdout);
#define all(x)       x.begin(), x.end()
#define ret(x)       {cout << x << endl; return;}

typedef pair<int, int> pii;
typedef pair<ll , ll > pll;

const int N     = 2e5+13;
const int LOG   = 23;
const int MOD   = 1e9 + 7; //998244353; //1e9+9;
const int INF   = 1e9; //1e18;
const int dx[4] = {1, -1, 0,  0};
const int dy[4] = {0,  0, 1, -1};

ll md(ll x) {x%=MOD; return (x < 0 ? x+MOD : x);}
ll GCD(ll _a, ll _b) { return (!_b ? _a : GCD(_b, _a % _b)); }
ll POW(ll _a, ll _b) { return !_b ? 1 : ((_b & 1 ? _a : 1) * POW(_a * _a % MOD, _b / 2)) % MOD;}

int n, x, ans;
int a[N], dp[N];
vector<int> vec;

void F() {
    cin >> n >> x;
    for(int i = 1; i <= n; i++) {
        cin >> a[i];
        a[i] *= -1;
    }
    vec.pb(a[n]);
    dp[n] = 1;
    int j;
    for(int i = n-1; i > 0; i--) {
        if(a[i] >= vec.back()) {
            vec.pb(a[i]);
            dp[i] = vec.size();
        }
        else {
            j = ub(all(vec), a[i]) - vec.begin();
            vec[j] = a[i];
            dp[i] = j + 1;
        }
    }
    for(int i = 1; i <= n; i++) {
        a[i] *= -1;
        a[i] -= x;
    }
    ans = dp[1];
    vec.clear();
    vec.pb(a[1]);
    int temp;
    for(int i = 2; i <= n; i++) {
        temp = lb(all(vec), a[i]+x) - vec.begin();
        ans = max(ans, temp + dp[i]);
        if(a[i] >= vec.back()) {
            vec.pb(a[i]);
        }
        else {
            j = ub(all(vec), a[i]) - vec.begin();
            vec[j] = a[i];
        }
    }
    ret(ans);
}

int32_t main() {
    migmig;
    //PREP();
    int t=1;
    //cin >> t;
    while(t--)
        F();
    return 0;
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 10
• Subtask 3: 0 / 13
• Subtask 4: 0 / 10
• Subtask 5: 0 / 20
• Subtask 6: 0 / 17
• Subtask 7: 0 / 25