제출 #1190411

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1190411		stefanopulos	K개의 묶음 (IZhO14_blocks)	C++20	100 / 100	508 ms	80688 KiB

blocks

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <bits/stdc++.h>
 
using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ldb;
 
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
typedef pair<ldb,ldb> pdd;

#define ff(i,a,b) for(int i = a; i <= b; i++)
#define fb(i,b,a) for(int i = b; i >= a; i--)
#define trav(a,x) for(auto& a : x)
 
#define sz(a) (int)(a).size()
#define fi first
#define se second
#define pb push_back
#define lb lower_bound
#define ub upper_bound
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
 
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

template<typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;

// os.order_of_key(k) the number of elements in the os less than k
// *os.find_by_order(k)  print the k-th smallest number in os(0-based)

const int mod = 1000000007;
const ll inf = (ll)1e15 + 5;
const int mxN = 100005; 

int n, K;
int niz[mxN];

ll dp[mxN][101];

int main(){
    cin.tie(0)->sync_with_stdio(0);

    cin >> n >> K;
    ff(i,1,n)cin >> niz[i];

    ff(i,0,n)ff(j,0,K)dp[i][j] = inf;

    dp[0][0] = 0;
    ff(j,1,K){

        stack<pll> stek;
        ff(i,1,n){

            ll mn = inf;
            while(sz(stek) > 0 && niz[stek.top().fi] <= niz[i]){
                mn = min(mn, stek.top().se);
                stek.pop();
            }

            int l = (sz(stek) == 0 ? 0 : stek.top().fi);
            dp[i][j] = min(dp[i][j], dp[l][j]);
            dp[i][j] = min(dp[i][j], dp[l][j - 1] + niz[i]);
            
            dp[i][j] = min(dp[i][j], mn + niz[i]);

            mn = min(mn, dp[i][j - 1]);
            stek.push({i, mn});

        }
    }

    cout << dp[n][K] << '\n';

    return 0;
}
/*

5 1
1 2 3 4 5

5 2
1 2 3 4 5

// probati bojenje sahovski
*/
 
 
 
 
 

• Subtask 1: 14 / 14
• Subtask 2: 18 / 18
• Subtask 3: 21 / 21
• Subtask 4: 47 / 47