Submission #1188021

#TimeUsernameProblemLanguageResultExecution timeMemory
1188021versesrevSplit the sequence (APIO14_sequence)C++20
33 / 100
105 ms2808 KiB
#include <iostream>
#include <vector>
#include <limits>
#include <numeric>
#include <algorithm>

int main() {
  int n, k;
  std::cin >> n >> k;
  std::vector<int> xs(n);
  for (int& x : xs) std::cin >> x;
  
  std::vector<long long> sum(n);
  std::partial_sum(xs.begin(), xs.end(), sum.begin());
  
  long long INF = std::numeric_limits<long long>::max();
  std::vector<std::vector<long long>> dp(k+1, std::vector<long long>(n, INF));
  std::vector<std::vector<int>> back(k+1, std::vector<int>(n, -1));
  for (int i = 0; i < n; ++i) {
    dp[0][i] = sum[i] * sum[i];
    back[0][i] = -1;
  }
  for (int ik = 1; ik <= k; ++ik) {
    for (int i = 0; i < n; ++i) {
      long long target = sum[i] / (ik + 1);
      int p = std::distance(sum.begin(), std::lower_bound(sum.begin(),
          sum.begin() + i,
          sum[i] - target));
      for (int j = std::max(p+1, ik); j <= i; ++j) {
        long long r = sum[i] - sum[j-1];
        if (r * (ik+1) > sum[i]) continue;
        long long v2 = sum[j-1]*sum[j-1]/ik + r*r;
        if (v2 >= dp[ik][i]) break;
        long long v = dp[ik-1][j-1] + r*r;
        if (dp[ik][i] >= v) {
          dp[ik][i] = v;
          back[ik][i] = j - 1;
        }
        else break;
      }
      for (int j = std::max(p+1, ik); j >= ik; --j) {
        long long r = sum[i] - sum[j-1];
        if (r * (ik+1) < sum[i]) continue;
        long long v2 = sum[j-1]*sum[j-1]/ik + r*r;
        if (v2 >= dp[ik][i]) break;
        long long v = dp[ik-1][j-1] + r*r;
        if (dp[ik][i] >= v) {
          dp[ik][i] = v;
          back[ik][i] = j - 1;
        }
        else break;
      }
    }
  }
  std::vector<int> ans;
  for (int p = n - 1, ik = k; ik; --ik) {
    p = back[ik][p];
    ans.push_back(p + 1);
  }
  std::ranges::reverse(ans);
  std::cout << ((sum[n-1] * sum[n-1] - dp[k][n-1]) / 2) << "\n";
  for (int v : ans) std::cout << v << " ";
  std::cout << "\n";
}
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