제출 #1186273

#제출 시각아이디문제언어결과실행 시간메모리
1186273asli_bgConstruction Project 2 (JOI24_ho_t2)C++20
100 / 100
287 ms30676 KiB
#include <bits/stdc++.h>
using namespace std;

#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;

#define int long long

typedef pair<int,int> pii;
typedef vector<int> vi;
typedef vector<pii> vii;
typedef vector<bool> vb;

typedef tree<pii,null_type,less<pii>,rb_tree_tag,
tree_order_statistics_node_update> oset;

#define fi first
#define se second
#define pb push_back
#define pf push_front

#define mid (l+r)/2
#define all(x) x.begin(),x.end()
#define FOR(i,a) for(int i=0;i<(a);i++)
#define FORE(i,a,b) for(int i=(a);i<(b);i++)

#define cont(x) for(auto el:x) cout<<el<<' ';cout<<endl;
#define contp(x) for(auto el:x) cout<<el.fi<<'-'<<el.se<<' ';cout<<endl;
#define sp <<" "<<

#define DEBUG(x) cout<<(#x) sp x<<endl
#define carp(a,b) (((a%MOD)*(b%MOD))%MOD)
#define topla(a,b) (((a%MOD)+(b%MOD))%MOD)

const int INF=1e18;
const int MAXN=2e5+5;
const int MOD=998244353;

int n,m,s,t,l,k;
vii adj[MAXN];

int d[MAXN];

vi vec;
int ans;

void dij(int bas){
    set<pii> ss;
    FORE(i,1,n+1) d[i]=INF;
    d[bas]=0;

    ss.insert({0,bas});

    while(!ss.empty()){
        auto el=*ss.begin();
        ss.erase(el);

        int nd=el.se;

        for(auto [kom,cost]:adj[nd]){
            if(d[kom]>d[nd]+cost){
                if(d[kom]!=INF) ss.erase({d[kom],kom});
                d[kom]=d[nd]+cost;
                ss.insert({d[kom],kom});
            }
        }
    }

    if(bas==t){
        FORE(i,1,n+1) vec.pb(d[i]);
        sort(all(vec));
    }
    else{
        FORE(i,1,n+1){
            int kalan=k-(d[i]+l);
            if(kalan<0) continue;

            auto it=upper_bound(all(vec),kalan)-vec.begin();
            ans+=it;
        }
    }
}

signed main(){

    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);

    cin>>n>>m;
    cin>>s>>t>>l>>k;

    FOR(i,m){
        int a,b,c;
        cin>>a>>b>>c;
        adj[a].pb({b,c});
        adj[b].pb({a,c});
    }

    ans=0;

    dij(t);
    dij(s);

    if(d[t]<=k) ans=n*(n-1)/2;

    //eğer sden tye zaten <=k da gidiyosam hepsi

    cout<<ans<<endl;
}
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