Submission #1185797

#TimeUsernameProblemLanguageResultExecution timeMemory
1185797avighnaBitaro, who Leaps through Time (JOI19_timeleap)C++20
0 / 100
2831 ms302308 KiB
#include <bits/stdc++.h> typedef long long ll; const ll inf = 1e15; struct Query { ll a, b, c, d; int i; }; void solve(int n, int q, std::vector<ll> &l, std::vector<ll> &r, std::vector<Query> &queries, std::vector<ll> &ans) { l.push_back(inf); r.push_back(inf + 1); const int lim = std::log2(n) + 1; std::vector ansl(n, std::vector<std::pair<ll, ll>>(lim)), ansr(n, std::vector<std::pair<ll, ll>>(lim)); for (int i = 0; i < n; ++i) { ansl[i][0] = {0, l[i] + 1}; ansr[i][0] = {0, r[i]}; // 0 jumps means we don't need anything if (i != n - 1) { ll v1 = std::max(0LL, ansl[i][0].second - (r[i + 1] - 1)); ll v2 = std::max(0LL, ansr[i][0].second - (r[i + 1] - 1)); ansl[i][0].first += v1; ansr[i][0].first += v2; ansl[i][0].second -= v1; ansr[i][0].second -= v2; } } auto _ansl = [&](int i, int x) -> std::pair<ll, ll> { ll cost = 0, time = l[i]; for (int bt = 0; bt < lim; ++bt) { if (x & (1 << bt)) { cost += ansl[i][bt].first; time = ansl[i][bt].second; i += (1 << bt); } } return {cost, time}; }; auto _ansr = [&](int i, int x) -> std::pair<ll, ll> { ll cost = 0, time = r[i] - 1; for (int bt = 0; bt < lim; ++bt) { if (x & (1 << bt)) { cost += ansr[i][bt].first; time = ansr[i][bt].second; i += (1 << bt); } } return {cost, time}; }; std::vector jump_min(n, std::vector<ll>(lim)), jump_max(n, std::vector<ll>(lim)); for (int i = 0; i < n; ++i) { jump_max[i][0] = l[i] - i; jump_min[i][0] = r[i] - i - 1; } for (int bt = 1; bt < lim; ++bt) { for (int i = 0; i < n; ++i) { jump_min[i][bt] = jump_min[i][bt - 1]; jump_max[i][bt] = jump_max[i][bt - 1]; if (i + (1 << (bt - 1)) < n) { jump_min[i][bt] = std::min(jump_min[i][bt], jump_min[i + (1 << (bt - 1))][bt - 1]); jump_max[i][bt] = std::max(jump_max[i][bt], jump_max[i + (1 << (bt - 1))][bt - 1]); } } } auto _ans = [&](int i, int x, ll t) -> std::pair<ll, ll> { int idx1 = i; ll max_val = l[i] - i; for (int bt = lim - 1; bt >= 0; --bt) { if (idx1 + (1 << bt) >= n) { continue; } if (std::max(max_val, jump_max[idx1 + 1][bt]) <= t - i) { max_val = std::max(max_val, jump_max[idx1 + 1][bt]); idx1 += 1 << bt; } } if (max_val <= t - i) { idx1 = std::min(n, idx1 + 1); } int idx2 = i; ll min_val = r[i] - i - 1; for (int bt = lim - 1; bt >= 0; --bt) { if (idx2 + (1 << bt) >= n) { continue; } if (t - i <= std::min(min_val, jump_min[idx2 + 1][bt])) { min_val = std::min(min_val, jump_min[idx2 + 1][bt]); idx2 += 1 << bt; } } if (t - i <= min_val) { idx2 = std::min(n, idx2 + 1); } ll free_jumps = std::max(0, std::min(idx1, idx2) - i); if (x <= free_jumps) { ll del = std::max(0LL, t + x - (r[i + x] - 1)); return {del, t + x - del}; } if (idx1 < idx2) { auto p = _ansl(idx1, x - free_jumps); return p; } else { auto p = _ansr(idx2, x - free_jumps); return {t + free_jumps - (r[idx2] - 1) + p.first, p.second}; } }; for (int bt = 1; bt < lim; ++bt) { for (int i = 0; i + (1 << bt) < n; ++i) { auto [ans1, t1] = _ans(i + (1 << (bt - 1)), 1 << (bt - 1), ansl[i][bt - 1].second); auto [ans2, t2] = _ans(i + (1 << (bt - 1)), 1 << (bt - 1), ansr[i][bt - 1].second); ansl[i][bt] = {ansl[i][bt - 1].first + ans1, t1}; ansr[i][bt] = {ansr[i][bt - 1].first + ans2, t2}; } } for (auto &[a, b, c, d, i] : queries) { if (a == c) { continue; } auto [cost, time] = _ans(a, c - a - 1, b); if (time < l[c - 1]) { time = l[c - 1]; } else if (time > r[c - 1] - 1) { cost += time - (r[c - 1] - 1); time = r[c - 1] - 1; } time++; if (time > d) { cost += time - d; } ans[i] = std::max(ans[i], cost); } l.pop_back(); r.pop_back(); } int main() { std::ios_base::sync_with_stdio(false); std::cin.tie(nullptr); int n, q; std::cin >> n >> q; std::vector<ll> l(n - 1), r(n - 1); for (int i = 0; i < n - 1; ++i) { std::cin >> l[i] >> r[i]; } std::vector<Query> q1, q2; for (int i = 0, a, b, c, d, t; i < q; ++i) { std::cin >> t >> a >> b >> c >> d; --a, --c; if (a <= c) { q1.push_back({a, b, c, d, i}); } else { q2.push_back({a, b, c, d, i}); } } std::vector<ll> ans(q); solve(n, q, l, r, q1, ans); // std::reverse(l.begin(), l.end()); // std::reverse(r.begin(), r.end()); // for (auto &[a, b, c, d, i] : q2) { // a = n - a - 1, c = n - c - 1; // } // solve(n, q, l, r, q2, ans); for (auto &i : ans) { std::cout << i << '\n'; } }
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