#include <bits/stdc++.h>
#define ar array
#define all(x) x.begin(), x.end()
using namespace std;
typedef long long ll;
const int N = 1e5 + 5, B = 300, lg = 17;
vector <int> g[N];
int st[lg][N], bit[N], d[N], n, m, q;
int c[N], tin[N], tout[N], tim = 0;
void dfs(int x, int par) {
tin[x] = ++tim; st[0][x] = par; d[x] = d[par] + 1;
for (int i = 1; i < lg; i++)
st[i][x] = st[i - 1][st[i - 1][x]];
for (int &y : g[x]) {
if (y != par) {
dfs(y, x);
}
}
tout[x] = tim;
}
void upd(int i, int qx) {
while (i <= n) {
bit[i] += qx;
i |= (i + 1);
}
}
int get(int i) {
int ans = 0;
while (i >= 0) {
ans += bit[i];
i = (i & (i + 1)) - 1;
}
return ans;
}
int get(int l, int r) {
return get(r) - get(l - 1);
}
int lca = -1, cnt[N], sm = 0, ans = 0;
void add(int x) {
if (lca == -1)
lca = x, ans++;
if (cnt[x] == 0) {
int sb = get(tin[x], tout[x]), nsb = sm - sb;
if (nsb > 0 && sb > 0)
return;
if (nsb == 0) {
ans += d[lca] - d[x];
lca = x;
} else {
int b = 16, y = x, res = 0;
while (b >= 0) {
int ty = st[b][y];
if (get(tin[ty], tout[ty]) == 0)
y = ty, res += (1 << b);
b--;
}
y = st[0][y];
if (sm == get(tin[y], tout[y]))
res++, lca = y;
ans += res + 1;
}
}
}
void rem(int x) {
cnt[x]--, sm--, upd(tin[x], -1);
if (cnt[x] == 0) {
int sb = get(tin[x], tout[x]), nsb = sm - sb;
if (nsb > 0 && sb > 0)
return;
if (sb == 0) {
}
}
}
int main() {
ios::sync_with_stdio(false);
cin.tie(0); cout.tie(0);
cin >> n >> m >> q;
for (int i = 1; i < n; i++) {
int u, v;
cin >> u >> v;
g[u].emplace_back(v);
g[v].emplace_back(u);
}
for (int i = 1; i <= m; i++)
cin >> c[i];
dfs(1, 0);
tout[0] = n;
while (q--) {
int l, r;
cin >> l >> r;
for (int i = l; i <= r; i++)
add(c[i]), cnt[c[i]]++, sm++, upd(tin[c[i]], 1);;
cout << ans << '\n';
for (int i = l; i <= r; i++)
cnt[c[i]] = 0, upd(tin[c[i]], -1);
sm = ans = 0; lca = -1;
}
return 0;
vector <ar <int, 3>> query(q);
vector <int> res(q);
for (int i = 0; i < q; i++)
cin >> query[i][0] >> query[i][1], query[i][2] = i;
sort(all(query), [] (const ar <int, 3> &a, const ar <int, 3> &b) {
if (a[0] / B == b[0] / B)
return a[1] < b[1];
return a[0] / B < b[0] / B;
});
}
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