# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
1181368 | karrigan | K blocks (IZhO14_blocks) | C11 | 0 ms | 0 KiB |
#include<bits/stdc++.h>
#define int long long
#define fi first
#define se second
#define pb push_back
#define ii pair<int, int>
#define sz(v) (int)v.size()
#define all(v) v.begin(), v.end()
using namespace std;
const int N = 1000, K = 1000, mod = 1e9+7, inf = 1e18;
int n, k;
int a[N];
int dp[N][K];
int mx[N][N];
signed main() {
ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
cin >> n >> k;
for (int i=1; i<=n; i++) cin >> a[i];
for (int i=1; i<=n; i++) {
for (int j=i; j<=n; j++) {
if(i==j) mx[i][j] = a[i];
else mx[i][j] = max(mx[i][j-1], a[j]);
}
}
for (int i=0; i<=n; i++) {
for (int j=0; j<=k; j++) dp[i][j] = inf;
}
for (int i=1; i<=n; i++) dp[i][1] = mx[1][i];
for (int j=2; j<=k; j++) {
for (int i=j; i<=n; i++) {
for (int l=1; l<i; l++) {
dp[i][j] = min(dp[i][j], dp[l][j-1]+mx[l+1][i]);
}
}
}
cout << dp[n][k];
}