제출 #1180338

#제출 시각아이디문제언어결과실행 시간메모리
1180338madamadam3메기 농장 (IOI22_fish)C++20
0 / 100
1095 ms9400 KiB
#include "fish.h"
#include <bits/stdc++.h>

using namespace std;

using vi = vector<int>;
typedef long long ll;

/*
  Time log:
  - first start: 1048am
  - 3/100: 1100am
  - 
  - first stop:
  - overall time used: 
*/

/*
  NxN grid of cells
  grid[c][r] = the cell at column c row r
  grid[0][r] is the westernmost point, and grid[N-1][r] is the easternmost point
  grid[c][0] = southernmost point, grid[c][N-1] northermost point

  M catfishes
  X[i], Y[i] for i < M are column and row of fish i
  W[i] = weight of fish i
  a catfish can be caught if grid[ci][ri] is empty and grid[ci-1][ri] or grid[ci+1][ri] has a pier tile
  a pier extends from grid[cP][0] to grid[cP][rP]
*/

ll max_weights(int N, int M, vi X, vi Y, vi W) {
  // subtask 2: x[i] <= 1: either use everything in col0, or col1 (as using 1 means you cant use the other)
  ll c0 = 0, c1 = 0;
  vi f0, f1;
  for (int i = 0; i < M; i++) {
    // cout << "i: " << i << " x: " << X[i] << " y: " << Y[i] << " W: " << W[i] << "\n";
    if (X[i] == 0) {
      c0 += W[i];
      f0.push_back(i);
    } else {
      c1 += W[i];
      f1.push_back(i);
    }
  }

  int Z = (int) f0.size(), &&O = (int) f1.size();
  // cout << "Z: " << Z << " O: " << O << "\n";
  int i = 0, j = 0;

  ll v = c1;
  ll ans = v;

  while (i < Z || j < O) {
    if (i >= Z || ((j < O) && Y[f1[j]] < Y[f0[i]])) {
      v -= W[f1[j]];
      j++;
    } else if (j >= O || ((i < Z) && Y[f0[i]] < Y[f1[j]])) {
      v += W[f0[i]];
      ans = max(ans, v);
      i++;
    }
  }

  return ans;
}
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