제출 #1178664

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1178664		8pete8	Koala Game (APIO17_koala)	C++20	74 / 100	35 ms	468 KiB

koala

#include "koala.h"
#include<bits/stdc++.h>
using namespace std;
#define pb push_back
int minValue(int N, int W) {
    // TODO: Implement Subtask 1 solution here.
    // You may leave this function unmodified if you are not attempting this
    // subtask.
    int B[N],R[N];
    for(int i=0;i<N;i++)B[i]=R[i]=0;
    B[0]=1;
    playRound(B,R);
    for(int i=0;i<N;i++)if(R[i]==0)return i;
    return 0;
}

int maxValue(int N, int W) {
    // TODO: Implement Subtask 2 solution here.
    // You may leave this function unmodified if you are not attempting this
    // subtask.
    int B[N],R[N];
    for(int i=0;i<N;i++)B[i]=1,R[i]=0;
    int c=2;
    for(int j=0;j<10;j++){
        playRound(B,R);
        int x=0,y=0;
        for(int j=0;j<N;j++){
            if(R[j]>1)x++,y=j;
        }
        if(x==1)return y;
        c=(W/x);
        for(int j=0;j<N;j++){
            if(R[j]>1)B[j]=c,x++,y=j;
            else B[j]=0;
        }
        if(x==1)return y;
    }
    //5 3 2 1 6 4
    return 0;
}

int greaterValue(int N, int W) {
    // TODO: Implement Subtask 3 solution here.
    // You may leave this function unmodified if you are not attempting this
    // subtask.
    int B[N],R[N];
    int l=1,r=min(9,N/2);
    while(l<=r){
        int mid=l+(r-l)/2;
        for(int i=0;i<N;i++)R[i]=B[i]=0;
        B[0]=B[1]=mid;
        playRound(B,R);
        if(R[0]==R[1]){
            if(R[0]==0)r=mid-1;
            else l=mid+1;
        }
        else return R[0]<R[1];
    }
    return 0;
}
int n,w;
int B[100],R[100];
int p[100];
bool cmp(int a,int b){
    for(int i=0;i<n;i++)B[i]=R[i]=0;
    B[a]=B[b]=61;
    playRound(B,R);
    B[a]=B[b]=0;
    if(R[a]==R[b])assert(0);
    int x=R[a]<R[b];
    R[a]=R[b]=0;
    return x;
}
bool cmp2(int a,int b){
    int l=1,r=9;
    while(l<=r){
        int mid=l+(r-l)/2;
        B[a]=B[b]=mid;
        playRound(B,R);
        B[a]=B[b]=0;
        if(R[a]==R[b]){
            if(R[a]==0)r=mid-1;
            else l=mid+1;
            R[a]=R[b]=0;
        }
        else{
            int x=(R[a]<R[b]);
            R[a]=R[b]=0;
            return x;
        }
    }
    return 0;
}

void ms(int l,int r){
    if(l==r)return;
    int mid=l+(r-l)/2;
    ms(l,mid);
    ms(mid+1,r);
    vector<int>done;
    int L=l,R=mid+1;
    while(L<=mid&&R<=r){
        if(cmp(p[L],p[R]))done.pb(p[L++]);
        else done.pb(p[R++]);
    }
    while(L<=mid)done.pb(p[L++]);
    while(R<=r)done.pb(p[R++]);
    for(int i=0;i<done.size();i++)p[i+l]=done[i];
}

void ms2(int l,int r){
    if(l==r)return;
    int mid=l+(r-l)/2;
    ms2(l,mid);
    ms2(mid+1,r);
    vector<int>done;
    int L=l,R=mid+1;
    while(L<=mid&&R<=r){
        if(cmp2(p[L],p[R]))done.pb(p[L++]);
        else done.pb(p[R++]);
    }
    while(L<=mid)done.pb(p[L++]);
    while(R<=r)done.pb(p[R++]);
    for(int i=0;i<done.size();i++)p[i+l]=done[i];
}
mt19937 rng(time(NULL));
void allValues(int N, int W, int *P) {
    n=N;
    w=W;
    for(int i=0;i<n;i++)p[i]=i,B[i]=R[i]=0;
    for(int i=0;i<n;i++)swap(p[i],p[rng()%(i+1)]);
    if (W == 2*N) {
        ms(0,n-1);
        for(int i=0;i<n;i++)P[p[i]]=i+1;
        // TODO: Implement Subtask 4 solution here.
        // You may leave this block unmodified if you are not attempting this
        // subtask.

    } else {
        ms2(0,n-1);
        for(int i=0;i<n;i++)P[p[i]]=i+1;
        // TODO: Implement Subtask 5 solution here.
        // You may leave this block unmodified if you are not attempting this
        // subtask.
    }
}

• Subtask 1: 4 / 4
• Subtask 2: 15 / 15
• Subtask 3: 18 / 18
• Subtask 4: 10 / 10
• Subtask 5: 27 / 53