Submission #117390

#	Time	Username	Problem	Language	Result	Execution time	Memory
117390		Abelyan	Global Warming (CEOI18_glo)	C++17	27 / 100	110 ms	10812 KiB

glo

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;

#define FOR(i,a) for (int i=0;i<(a);++i)
#define FORD(i,a) for (int i=(a)-1;i>=0;i--)
#define FORT(i,a,b) for (int i=(a);i<=(b);++i)
#define FORTD(i,b,a) for (int i=(b);i>=(a);--i)
#define trav(i,v) for (auto i : v)
#define all(v) v.begin(),v.end()
#define ad push_back
#define fr first
#define sc second
#define mpr(a,b) make_pair(a,b)
#define pir pair<int,int>
#define all(v) v.begin(),v.end()
#define make_unique(v) v.erase(unique(all(v),v.end()))
#define fastio ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);
#define dbg(x);
#define dbgv(v);
#define srng mt19937 rng(chrono::steady_clock::now().time_since_epoch().count())
#define y1 EsiHancagorcRepa
#ifdef ALEXPC
#define dbg(x); cout<<#x<<" = "<<x<<endl
#define dbgv(v); cout<<#v<<" = ["; trav(tv,v)cout<<"tv,";cout<<"]"<<endl
#endif

//const int N=100,M=N*N;
const ll MOD=1000*1000*1000+7;

const int N=1e6+6;

int a[N];

vector<int> lis1(N),lis2(N);

int main(){
    fastio;
    srng;
    int n,x;
    cin>>n>>x;
    fill(all(lis1),INT_MAX);
    fill(all(lis2),INT_MAX);
    FOR(i,n){
        cin>>a[i];
        //cout<<a[i]<<endl;
        //lis2[max(lower_bound(all(lis1),a[i]+x)-lis1.begin(),lower_bound(all(lis2),a[i])-lis2.begin())]=a[i];
        //cout<<i<<endl;
        //cout<<endl;
        lis2[lower_bound(all(lis1),a[i])-lis1.begin()]=min(lis2[lower_bound(all(lis1),a[i])-lis1.begin()],a[i]);
        //FOR(j,n)cout<<lis2[j]<<" ";
        //cout<<endl;
        lis2[lower_bound(all(lis1),a[i]+x)-lis1.begin()]=min(lis2[lower_bound(all(lis1),a[i]+x)-lis1.begin()],a[i]+x);
        //FOR(j,n)cout<<lis2[j]<<" ";
        //cout<<endl;
        *lower_bound(all(lis2),a[i]+x)=a[i]+x;
        //FOR(j,n)cout<<lis2[j]<<" ";
        //cout<<endl;
        *lower_bound(all(lis1),a[i])=a[i];
        //FOR(j,n)cout<<lis2[j]<<" ";



    }
    FOR(i,n){
        if (lis2[i]==INT_MAX){
            cout<<i<<endl;
            return 0;
        }


    }
    return 0;
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 10
• Subtask 3: 0 / 13
• Subtask 4: 10 / 10
• Subtask 5: 0 / 20
• Subtask 6: 17 / 17
• Subtask 7: 0 / 25