제출 #1169753

#제출 시각아이디문제언어결과실행 시간메모리
1169753SmuggingSpunRoad Construction (JOI21_road_construction)C++20
65 / 100
10091 ms104576 KiB
#include<bits/stdc++.h> #define taskname "B" using namespace std; typedef long long ll; template<class T>void minimize(T& a, T b){ if(a > b){ a = b; } } template<class T>void maximize(T& a, T b){ if(a < b){ a = b; } } const int lim = 25e4 + 5; const ll LIM = 4e9; int n, k, x[lim], y[lim]; namespace sub1{ void solve(){ vector<ll>a; for(int i = 1; i < n; i++){ for(int j = i + 1; j <= n; j++){ a.emplace_back(ll(abs(x[i] - x[j])) + abs(y[i] - y[j])); } } sort(a.begin(), a.end()); for(int i = 0; i < k; i++){ cout << a[i] << "\n"; } } } namespace sub2{ void solve(){ sort(x + 1, x + n + 1); int low = 1, high = 2e9, d; while(low <= high){ int mid = (low + high) >> 1LL, cnt = 0; for(int i = 1, j = 1; i <= n && cnt < k; i++){ while(x[i] - x[j] > mid){ j++; } cnt += i - j; } if(cnt >= k){ high = (d = mid) - 1; } else{ low = mid + 1; } } vector<int>ans; for(int i = 1; i <= n; i++){ for(int j = i - 1; j > 0 && x[i] - x[j] < d; j--){ ans.emplace_back(x[i] - x[j]); } } sort(ans.begin(), ans.end()); for(int& x : ans){ cout << x << "\n"; } for(int i = ans.size(); i < k; i++){ cout << d << "\n"; } } } namespace sub3456{ const int INF = 2e9 + 1; struct Node{ int cnt, l, r; Node(){ this->cnt = 0; this->l = this->r = -1; } }; int N_y; vector<int>_x(1, -INF), _y(1, -INF); vector<Node>st(1, Node()); void build(int id, int l, int r){ if(l == r){ return; } int m = (l + r) >> 1; st[id].l = st.size(); st.emplace_back(Node()); st[id].r = st.size(); st.emplace_back(Node()); build(st[id].l, l, m); build(st[id].r, m + 1, r); } void update(int id, int l, int r, int p){ st[id].cnt++; if(l == r){ return; } int m = (l + r) >> 1; if(m < p){ st.emplace_back(st[st[id].r]); st[id].r = int(st.size()) - 1; update(st[id].r, m + 1, r, p); } else{ st.emplace_back(st[st[id].l]); st[id].l = int(st.size()) - 1; update(st[id].l, l, m, p); } } int get(int id, int l, int r, int u, int v){ if(l > v || r < u){ return 0; } if(u <= l && v >= r){ return st[id].cnt; } ll m = (l + r) >> 1LL; return get(st[id].l, l, m, u, v) + get(st[id].r, m + 1, r, u, v); } int get(ll X, ll yl, ll yr){ minimize(X, ll(INF)); maximize(X, ll(-INF)); maximize(yl, ll(-INF)); minimize(yr, ll(INF)); return get(upper_bound(_x.begin(), _x.end(), X) - _x.begin() - 1, 0, N_y - 1, lower_bound(_y.begin(), _y.end(), yl) - _y.begin(), upper_bound(_y.begin(), _y.end(), yr) - _y.begin() - 1); } void solve(){ for(int i = 1; i <= n; i++){ _x.emplace_back(x[i] += y[i]); _y.emplace_back(y[i] = x[i] - (y[i] << 1LL)); } sort(_x.begin(), _x.end()); _x.resize(unique(_x.begin(), _x.end()) - _x.begin()); sort(_y.begin(), _y.end()); _y.resize(unique(_y.begin(), _y.end()) - _y.begin()); N_y = _y.size(); vector<int>p(n); iota(p.begin(), p.end(), 1); sort(p.begin(), p.end(), [&] (int i, int j){ return x[i] < x[j]; }); for(int i = 1; i < _x.size(); i++){ st.emplace_back(Node()); } build(0, 0, N_y - 1); int j = 0; for(int& i : p){ if(x[i] != _x[j]){ j++; st[j] = st[j - 1]; } update(j, 0, N_y - 1, lower_bound(_y.begin(), _y.end(), y[i]) - _y.begin()); } ll low = 1, high = LIM, d; while(low <= high){ ll mid = (low + high) >> 1LL; int cnt = 0; for(int i = 1; i <= n && (cnt >> 1) < k; i++){ cnt += get(mid + x[i], -mid + y[i], mid + y[i]) - get(-mid - 1 + x[i], -mid + y[i], mid + y[i]) - 1; } if((cnt >> 1) >= k){ high = (d = mid) - 1; } else{ low = mid + 1; } } set<pair<int, int>>S; vector<ll>ans; if(d > 1){ for(int i = 0, j = 0; i < n; i++){ while(x[p[i]] - x[p[j]] >= d){ S.erase(make_pair(y[p[j]], x[p[j]])); j++; } for(auto it = S.lower_bound(make_pair(y[p[i]] - d + 1, -1)); it != S.end() && (*it).first < y[p[i]] + d; it = next(it)){ ans.emplace_back(max(abs(ll(x[p[i]]) - (*it).second), abs(ll(y[p[i]]) - (*it).first))); } S.emplace(y[p[i]], x[p[i]]); } sort(ans.begin(), ans.end()); for(ll& x : ans){ cout << x << "\n"; } } for(int i = ans.size(); i < k; i++){ cout << d << "\n"; } } } int main(){ ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); if(fopen(taskname".inp", "r")){ freopen(taskname".inp", "r", stdin); } cin >> n >> k; for(int i = 1; i <= n; i++){ cin >> x[i] >> y[i]; } if(n <= 1000){ sub1::solve(); } else if(count(y + 1, y + n + 1, 0) == n){ sub2::solve(); } else{ sub3456::solve(); } }

컴파일 시 표준 에러 (stderr) 메시지

road_construction.cpp: In function 'int main()':
road_construction.cpp:191:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  191 |         freopen(taskname".inp", "r", stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~
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