#include <bitset>
#include <iostream>
#include <map>
#include <set>
#include <unordered_set>
#include <queue>
using namespace std;
#define ll long long
int n,k;
char c;
ll asp=0;
// 10000000040
unordered_set<ll> ban[2],fp;
ll read()
{
asp=0;
for(int i=0;i<n;i++)
{
cin>>c;
asp<<=1;
asp+=c-'0';
}
return asp;
}
ll pw2[70];
int main()
{
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin>>n>>k;
pw2[0]=1;
for(int i=1;i<=n;i++)
pw2[i]=2ll*pw2[i-1];
ll st=read(),ed=read();
for(int i=0;i<k;i++)
{
ll c=read();
fp.insert(c);
// ban[0].insert(c);
// ban[1].insert(c);
}
// lets do a double sided bfs
// better time complexity
queue<ll>pq;
ban[0].insert(st);
pq.push(st);
ban[1].insert(ed);
pq.push(ed);
ll op=0;
while(pq.size())
{
ll x=pq.front();
pq.pop();
op++;
bool p=ban[0].find(x)!=end(ban[0]);
bool q=ban[1].find(x)!=end(ban[1]);
if(p and q)
{
cout<<"TAK"<<endl;
return 0;
}
// if(op*n >= 2e9)
// {
// break;
// }
for(int bi=0;bi<n;bi++)
{
ll y=x^pw2[bi];
if(fp.find(c)!=fp.end())continue;
if(p and ban[0].find(y)==end(ban[0]))
{
if(ban[1].find(y)!=end(ban[1]))
{
cout<<"TAK"<<endl;
return 0;
}
ban[0].insert(y);
pq.push(y);
}
if(q and ban[1].find(y)==end(ban[1]))
{
if(ban[0].find(y)!=end(ban[0]))
{
cout<<"TAK"<<endl;
return 0;
}
ban[1].insert(y);
pq.push(y);
}
}
}
cout<<"NIE"<<endl;
return 0;
}
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