Submission #1167072

#TimeUsernameProblemLanguageResultExecution timeMemory
1167072KickingKunMeetings (IOI18_meetings)C++20
0 / 100
5593 ms1708 KiB
#include "meetings.h" #include <bits/stdc++.h> using namespace std; #define ll long long const int N = 1e5 + 2, SQR = 400; int nxtL[N], nxtR[N]; vector <int> height; ll dnc(int l, int r, int u, int v) { if (u > v) return 1e15; if (u == v) { int ans = 0; for (int i = u; i >= l;) { int k = max(l, nxtL[i] + 1); ans += height[i] * (i - k + 1); i = k - 1; } for (int i = u; i <= r;) { int k = min(r, nxtR[i] - 1); ans += height[i] * (k - i + 1); i = k + 1; } return ans -= height[u]; } int mid = (l + r) >> 1; ll ans = 1e15; vector <int> le, ri; for (int i = mid; i >= l; i = nxtL[i]) le.emplace_back(i); reverse(le.begin(), le.end()); for (int i = mid + 1; i <= r; i = nxtR[i]) ri.emplace_back(i); int id = ri.size() - 1, sum = 0; for (int pos: le) { int k = max(nxtL[pos] + 1, l); // k -> pos int R = nxtR[pos]; while (id >= 0 && ri[id] >= R) { if (id == ri.size() - 1) sum += (r - ri[id] + 1) * height[ri[id]]; else sum += (ri[id + 1] - ri[id]) * height[ri[id]]; --id; } ans = min(ans, dnc(l, mid, max(k, u), min(pos, v)) + height[pos] * (R - 1 - mid) + sum); } reverse(ri.begin(), ri.end()); id = 0, sum = 0; for (int pos: ri) { int k = min(nxtR[pos] - 1, r); int L = nxtL[pos]; while (id < le.size() && le[id] <= L) { if (id == 0) sum += (le[id] - l + 1) * height[le[id]]; else sum += (le[id] - le[id - 1]) * height[le[id]]; ++id; } ans = min(ans, dnc(mid + 1, r, max(u, pos), min(v, k)) + height[pos] * (mid - L) + sum); } return ans; } vector <ll> minimum_costs(vector <int> H, vector <int> L, vector <int> R) { height = H; int n = H.size(); stack <int> st; for (int i = 0; i < n; i++) { while (!st.empty() && H[st.top()] <= H[i]) st.pop(); nxtL[i] = (st.empty() ? -1 : st.top()); st.emplace(i); } while (!st.empty()) st.pop(); for (int i = n - 1; i >= 0; i--) { while (!st.empty() && H[st.top()] <= H[i]) st.pop(); nxtR[i] = (st.empty() ? n : st.top()); st.emplace(i); } vector <ll> ans; for (int i = 0; i < L.size(); i++) ans.emplace_back(dnc(L[i], R[i], L[i], R[i])); return ans; }
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