제출 #1166367

#제출 시각아이디문제언어결과실행 시간메모리
1166367merciless_lassieCommuter Pass (JOI18_commuter_pass)C++20
31 / 100
199 ms18584 KiB
#include "bits/stdc++.h"
using namespace std;
#define int long long

const int INF = 1e18;

int n, m, s, t, u, v;
vector<pair<int, int>> graph[100005];

// Standard Dijkstra to compute shortest distances from a source
vector<int> dijkstra(int src) {
    vector<int> dist(n + 1, INF);
    priority_queue<pair<int, int>, vector<pair<int, int>>, greater<>> pq;
    
    dist[src] = 0;
    pq.push({0, src});
    
    while (!pq.empty()) {
        int d = pq.top().first;
        int node = pq.top().second;
        pq.pop();
        
        if (d > dist[node]) continue;
        
        for (auto [next, weight] : graph[node]) {
            if (dist[node] + weight < dist[next]) {
                dist[next] = dist[node] + weight;
                pq.push({dist[next], next});
            }
        }
    }
    return dist;
}

// Modified Dijkstra for U to V considering S-T shortest paths
int dijkstra_uv_with_pass(vector<int>& dist_s, vector<int>& dist_t) {
    vector<int> dist(n + 1, INF);
    priority_queue<pair<int, int>, vector<pair<int, int>>, greater<>> pq;
    
    dist[u] = 0;
    pq.push({0, u});
    
    while (!pq.empty()) {
        int d = pq.top().first;
        int node = pq.top().second;
        pq.pop();
        
        if (d > dist[node]) continue;
        
        for (auto [next, weight] : graph[node]) {
            // Check if this edge can be on some S-T shortest path
            bool is_free = (dist_s[node] + weight + dist_t[next] == dist_s[t]) ||
                           (dist_s[next] + weight + dist_t[node] == dist_s[t]);
            int cost = is_free ? 0 : weight;
            
            if (dist[node] + cost < dist[next]) {
                dist[next] = dist[node] + cost;
                pq.push({dist[next], next});
            }
        }
    }
    return dist[v];
}

int solve() {
    // Compute shortest distances from S and T
    vector<int> dist_s = dijkstra(s);
    vector<int> dist_t = dijkstra(t);
    
    if (dist_s[t] == INF) return -1; // No path from S to T (shouldn't happen per constraints)
    
    // Compute minimum cost from U to V considering the commuter pass
    return dijkstra_uv_with_pass(dist_s, dist_t);
}

signed main() {
    ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
    
    cin >> n >> m;
    cin >> s >> t >> u >> v;
    
    for (int i = 0; i < m; i++) {
        int a, b, c;
        cin >> a >> b >> c;
        graph[a].push_back({b, c});
        graph[b].push_back({a, c});
    }
    
    cout << solve() << endl;
    
    return 0;
}
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