제출 #1166306

#제출 시각아이디문제언어결과실행 시간메모리
1166306MPG건물 4 (JOI20_building4)C++20
100 / 100
151 ms49500 KiB
//#pragma GCC optomize("Ofast") //#pragma GCC optimize("unroll-loops") //#pragma GCC optimize("O3") //#pragma GCC target("avx2") //#pragma GCC target("sse,sse2,sse4.1,sse4.2") #include <bits/stdc++.h> using namespace std; typedef long long ll; #define max_heap priority_queue<pair <ll, pair <ll, ll>>> //#define min_heap priority_queue<pair <ll, ll>, vector<pair <ll, ll>>, greater<pair <ll, ll>>> #define min_heap priority_queue<pair <ll, pair <ll, ll>>, vector<pair <ll, pair <ll, ll>>>, greater<pair <ll, pair <ll, ll>>>> #define sariE cin.tie(NULL); cout.tie(NULL); ios_base::sync_with_stdio(false); #define filE freopen("in.txt", "r", stdin);// freopen("out1.txt", "w", stdout); #define endl '\n' #define md(a) (a % mod + mod) % mod #define pb push_back //mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); //cout << setprecision(5) << fixed << f; //hash prime = 769 ll const maxn = 1e6 + 123; ll const inf = 3e18; ll const loG = 18; // 23 ll const mod = 1e9 + 7; //ll const mod = 998244353; ll const sq = 500; ll power(ll a, ll b, ll mod){if(b==0)return 1;if(b==1)return a;ll x = power(a, b / 2, mod);return (((x * x) % mod) * (b % 2 ? a : 1)) % mod;} ll n, arr[maxn][2], mx[maxn][2], mn[maxn][2]; string s; void Solve(){ cin >> n; for(int i = 1; i < 2 * n + 1; i++) cin >> arr[i][0]; for(int i = 1; i < 2 * n + 1; i++) cin >> arr[i][1]; for(int i = 1; i <= 2 * n; i++) { mx[i][0] = mx[i][1] = -inf; mn[i][0] = mn[i][1] = inf; } for(int i = 1; i <= 2 * n; i++) { if (arr[i][0] >= arr[i - 1][0]){ mx[i][0] = max(mx[i - 1][0], mx[i][0]); mn[i][0] = min(mn[i - 1][0], mn[i][0]); } if (arr[i][1] >= arr[i - 1][0]){ mx[i][1] = max(mx[i][1], mx[i - 1][0] + 1); mn[i][1] = min(mn[i][1], mn[i - 1][0] + 1); } if (arr[i][0] >= arr[i - 1][1]){ mx[i][0] = max(mx[i - 1][1], mx[i][0]); mn[i][0] = min(mn[i - 1][1], mn[i][0]); } if (arr[i][1] >= arr[i - 1][1]){ mx[i][1] = max(mx[i][1], mx[i - 1][1] + 1); mn[i][1] = min(mn[i][1], mn[i - 1][1] + 1); } } ll chi; if (mn[2 * n][0] <= n && mx[2 * n][0] >= n) chi = 0; else if (mn[2 * n][1] <= n && mx[2 * n][1] >= n) chi = 1; else{ cout << -1 << endl; return; } ll bag = n; for (int i = 2 * n - 1; i >= 0; i--){ if (chi) s.pb('B'); else s.pb('A'); bag -= chi; if ( (mx[i][chi] < bag) || (mn[i][chi] > bag) || ((i > 1) && (arr[i + 1][chi] < arr[i][chi]))) chi = 1 - chi; } reverse(s.begin(), s.end()); cout << s << endl; } int main(){ sariE; //filE; int test = 1; //cin >> test; while (test--) Solve(); return 0; }
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