Submission #1166096

#	Time	Username	Problem	Language	Result	Execution time	Memory
1166096		dzhoz0	K개의 묶음 (IZhO14_blocks)	C++20	0 / 100	37 ms	82504 KiB

blocks

/*
    ghmt the cutie :3
          UwU
*/

#include <bits/stdc++.h>
using namespace std;

#define int long long
#define INF 1e18
#define f first
#define s second
#define pii pair<int, int>
#define vi vector<int>

const int MOD = 1'000'000'000 + 7;

void setIO(string name = "")
{
    ios_base::sync_with_stdio(0);
    cin.tie(0), cout.tie(0);
#ifdef LOCAL
    freopen("inp.txt", "r", stdin);
    freopen("out.txt", "w", stdout);
#else
    if (!name.empty())
    {
        freopen((name + ".INP").c_str(), "r", stdin);
        freopen((name + ".OUT").c_str(), "w", stdout);
    }
#endif
}

const int MAXN = 1e5, MAXK = 100;
int n, k;
int a[MAXN + 5];
int dp[MAXN + 5][MAXK + 5];

void solve()
{
    cin >> n >> k;
    for(int i = 1; i <= n; i++) cin >> a[i];

    memset(dp, 0, sizeof(dp));
    for(int i = 1; i <= n; i++) { 
        for(int j = 1; j <= k; j++) {
            dp[i][j] = INF;
        }
    } 
    
    sort(a + 1, a + n + 1);
    int res = INF;

    for(int i = 1; i <= n; i++) {
        dp[i][1] = a[i];
        for(int j = 2; j <= min(i, k); j++) {
            for(int l = j - 1; l < i; l++) {
                dp[i][j] = min(dp[i][j], dp[l][j - 1] + a[i]);
            } 
        }
    }

    cout << dp[n][k] << '\n';
}
signed main()
{
    setIO();
    int t = 1;
    // cin >> t;
    while (t--)
        solve();
}

Compilation message (stderr)

blocks.cpp: In function 'void setIO(std::string)':
blocks.cpp:28:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   28 |         freopen((name + ".INP").c_str(), "r", stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
blocks.cpp:29:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   29 |         freopen((name + ".OUT").c_str(), "w", stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 0 / 14
• Subtask 2: 0 / 18
• Subtask 3: 0 / 21
• Subtask 4: 0 / 47