제출 #1162675

#제출 시각아이디문제언어결과실행 시간메모리
1162675Zero_OPMarathon Race 2 (JOI24_ho_t3)C++20
7 / 100
0 ms328 KiB
#include <bits/stdc++.h> using namespace std; #define FOR(i, l, r) for(int i = (l); i < (r); ++i) #define ROF(i, r, l) for(int i = (r) - 1; i >= (l); --i) #define mp make_pair #define mt make_tuple #define ff first #define ss second #define all(v) begin(v), end(v) #define rall(v) rbegin(v), rend(v) #define pb push_back #define eb emplace_back #define sz(v) (int)v.size() #define sum_of(v) accumulate(all(v), 0ll) #define dbg(x) "[" #x " = " << (x) << "]" template<typename T> bool minimize(T& a, const T& b){ if(a > b) return a = b, true; return false; } template<typename T> bool maximize(T& a, const T& b){ if(a < b) return a = b, true; return false; } using ll = long long; using db = double; using ld = long double; using ull = unsigned long long; using pi = pair<int, int>; using pl = pair<ll, ll>; using pd = pair<db, db>; using vi = vector<int>; using vb = vector<bool>; using vc = vector<char>; using vl = vector<ll>; using vd = vector<db>; using vpi = vector<pi>; using vpl = vector<pl>; void setIO(){ ios_base::sync_with_stdio(0); cin.tie(0); #ifdef LOCAL freopen("task.inp", "r", stdin); freopen("task.out", "w", stdout); #endif // LOCAL } const int MAX = 5e5 + 5; int N, L, M, X[MAX], v[MAX], c[MAX]; ll pref[MAX], suff[MAX]; int main(){ setIO(); cin >> N >> L; FOR(i, 0, N) cin >> X[i]; sort(X, X + N); FOR(i, 0, N){ if(!M || v[M] != X[i]){ ++M; v[M] = X[i]; c[M] = 1; } else ++c[M]; } FOR(i, 1, M+1) pref[i] = pref[i-1] + c[i]; ROF(i, M+1, 1) suff[i] = suff[i+1] + c[i]; int Q; cin >> Q; while(Q--){ int S, G, T; cin >> S >> G >> T; ll best = 1e18; //move from i to 1 then to M ll A = abs(S - v[1]) + abs(G - v[M]) * 1LL * (N+1); FOR(j, 1, M) A += 1LL * (v[j+1] - v[j]) * (pref[j]+1); minimize(best, A); //move from i to M then to i ll B = abs(S - v[M]) + abs(G - v[1]) * 1LL * (N+1); ROF(j, M, 1) B += 1LL * (v[j+1] - v[j]) * (suff[j+1]+1); minimize(best, B); FOR(i, 1, M+1){ //i -> 1 -> M -> i ll C = abs(S - v[1]) + abs(G - v[i]) * 1LL * (N+1) + 1LL * (v[M] - v[i]) * (pref[i-1] + 1); FOR(j, 1, i) C += 1LL * (v[j+1] - v[j]) * (pref[j]+1); FOR(j, i, M) C += 1LL * (v[j+1] - v[j]) * (suff[j+1] + 1 + pref[i-1]); minimize(best, C); //i -> M -> 1 -> i ll D = abs(S - v[M]) + abs(G - v[i]) * 1LL * (N+1) + 1LL * (v[i] - v[1]) * (suff[i+1] + 1); ROF(j, M, i) D += 1LL * (v[j+1] - v[j]) * (suff[j+1] + 1); FOR(j, 1, i) D += 1ll * (v[j+1] - v[j]) * (pref[i] + 1 + suff[i+1]); minimize(best, D); // cout << dbg(C) << dbg(D) << '\n'; } best += N; // cout << dbg(best) << '\n'; cout << (best <= T ? "Yes\n" : "No\n"); } return 0; }
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