제출 #1161800

#제출 시각아이디문제언어결과실행 시간메모리
1161800Zero_OPCoin Collecting (JOI19_ho_t4)C++20
8 / 100
703 ms488 KiB
#include <bits/stdc++.h> using namespace std; #define FOR(i, l, r) for(int i = (l); i < (r); ++i) #define ROF(i, r, l) for(int i = (r) - 1; i >= (l); --i) #define mp make_pair #define mt make_tuple #define ff first #define ss second #define all(v) begin(v), end(v) #define rall(v) rbegin(v), rend(v) #define sz(v) (int)v.size() #define pb push_back #define eb emplace_back #define compact(v) v.erase(unique(all(v)), end(v)) #define dbg(x) "[" #x " = " << (x) << "]" template<typename T> bool minimize(T& a, const T& b){ if(a > b) return a = b, true; return false; } template<typename T> bool maximize(T& a, const T& b){ if(a < b) return a = b, true; return false; } using ll = long long; using db = double; using ld = long double; using ull = unsigned long long; using pi = pair<int, int>; using pl = pair<ll, ll>; using pd = pair<db, db>; using vi = vector<int>; using vl = vector<ll>; using vb = vector<bool>; using vc = vector<char>; using vd = vector<db>; using vpi = vector<pi>; using vpl = vector<pl>; void setIO(){ ios_base::sync_with_stdio(0); cin.tie(0); #ifdef LOCAL freopen("task.inp", "r", stdin); freopen("task.ans", "w", stdout); #endif // LOCAL } ll dist(ll x1, ll y1, ll x2, ll y2){ return abs(x1 - x2) + abs(y1 - y2); } int main(){ setIO(); int N; cin >> N; vi X(2 * N), Y(2 * N); ll base = 0; FOR(i, 0, 2*N){ cin >> X[i] >> Y[i]; tuple<ll, int, int> best(1e18, 0, 0); if(1 <= X[i] && X[i] <= N){ tuple<ll, int, int> U(dist(X[i], 2, X[i], Y[i]), X[i], 2); tuple<ll, int, int> D(dist(X[i], 1, X[i], Y[i]), X[i], 1); best = min(U, D); } else{ tuple<ll, int, int> DL(dist(1, 1, X[i], Y[i]), 1, 1); tuple<ll, int, int> DR(dist(N, 1, X[i], Y[i]), N, 1); tuple<ll, int, int> UL(dist(1, 2, X[i], Y[i]), 1, 2); tuple<ll, int, int> UR(dist(N, 2, X[i], Y[i]), N, 2); best = min({DL, DR, UL, UR}); } ll cost; int x, y; tie(cost, x, y) = best; X[i] = x; Y[i] = y; base += cost; } vector<array<int, 2>> cnt(N); ll ans = LLONG_MAX; FOR(mask, 0, (1 << (2 * N))){ vi a, b; ll result = 0; FOR(i, 0, 2 * N){ if(mask >> i & 1){ if(Y[i] == 2) a.pb(X[i]); else b.pb(X[i]); ++result; } else{ if(Y[i] == 1) a.pb(X[i]); else b.pb(X[i]); } } if(sz(a) == N && sz(b) == N){ sort(all(a)); sort(all(b)); FOR(i, 0, N){ result += abs(i+1 - a[i]); result += abs(i+1 - b[i]); } minimize(ans, result); } } cout << ans + base << '\n'; return 0; }
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