제출 #1159510

#제출 시각아이디문제언어결과실행 시간메모리
1159510jotinhaBitaro’s Party (JOI18_bitaro)C++20
7 / 100
2094 ms12332 KiB
/** * author: Jotinha (ツ) * created: 02-28-2025 11:09:44 **/ #include <bits/stdc++.h> using namespace std; #ifdef LOCAL #include "algo/debug.h" #else #define debug(...) 42 #endif int main() { ios::sync_with_stdio(false); cin.tie(0); int n, m, q; cin >> n >> m >> q; vector<vector<int>> g(n); for(int i = 0; i < m; i++) { int u, v; cin >> u >> v; --u, --v; g[u].push_back(v); g[v].push_back(u); } vector<int> tot(n); vector<vector<pair<int, vector<int>>>> qr(n); int t = 0; for(int i = 0; i < q; i++) { int u, k; cin >> u >> k; --u; vector<int> v(k); for(int& j : v) { cin >> j; --j; } qr[u].emplace_back(make_pair(t++, v)); tot[u] += (int) v.size(); } auto bfs = [&](int u) { vector<int> dist(n, -1); queue<int> qe; qe.emplace(u); dist[u] = 0; while(!qe.empty()) { auto v = qe.front(); qe.pop(); for(int nxt : g[v]) { if(nxt < v && dist[nxt] < dist[v] + 1) { dist[nxt] = dist[v] + 1; qe.push(nxt); } } } return dist; }; const int sq = 500; const int inf = 0x3f3f3f3f; vector<vector<pair<int, int>>> dp(n, vector<pair<int, int>> (sq, make_pair(-inf, inf))); vector<int> vis(n); function<void(int)> dfs = [&](int u) { if(vis[u]) { return; } vector<pair<int, int>> wait { {0, u} }; for(int nxt : g[u]) { if(nxt < u) { dfs(nxt); for(int i = 0; i < sq && dp[nxt][i].first >= 0; i++) { wait.emplace_back(dp[nxt][i].first + 1, dp[nxt][i].second); } } } sort(wait.rbegin(), wait.rend()); wait.erase(unique(wait.begin(), wait.end()), wait.end()); for(int i = 0; i < sq && i < (int) wait.size(); i++) { dp[u][i] = wait[i]; } vis[u] = 1; }; vector<int> ans(t, -1); for(int i = n - 1; i >= 0; i--) { if(tot[i] >= sq) { auto dist = bfs(i); multiset<int> ms(dist.begin(), dist.end()); ms.insert(-1); for(int j = 0; j < qr[i].size(); j++) { for(int nxt : qr[i][j].second) { ms.erase(ms.find(dist[nxt])); } ans[qr[i][j].first] = *ms.rbegin(); for(int nxt : qr[i][j].second) { ms.insert(dist[nxt]); } } } else { dfs(i); for(int j = 0; j < sq; j++) { for(int k = 0; k < qr[i].size(); k++) { if(ans[qr[i][k].first] == -1) { int show = 1; for(int nxt : qr[i][k].second) { if(nxt == dp[i][j].second) { show = 0; break; } } if(show) { ans[qr[i][k].first] = dp[i][j].first; } } } } } } for(int x : ans) { cout << (x < 0 ? -1 : x) << '\n'; } return 0; }
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