제출 #1158490

#제출 시각아이디문제언어결과실행 시간메모리
1158490countlessCyberland (APIO23_cyberland)C++20
44 / 100
951 ms2162688 KiB
#include "cyberland.h" #include <vector> #include <queue> #include <iostream> #include <math.h> using namespace std; typedef long long ll; typedef unsigned long long ull; typedef long double ld; const ld INF = 9e18; struct T { ld cdist; int k; int node; bool operator>(const T &other) const { if (cdist != other.cdist) return cdist > other.cdist; if (k != other.k) return k > other.k; return node > other.node; } }; ld divByPow2(int x, int k) { return x / (ull)pow(2, k); } void checkReal(int start, int H, vector<vector<pair<int, int>>> &adj, vector<bool> &real) { real[start] = true; if (start == H) return; for (const pair<int, int> &i : adj[start]) { if (!real[i.first]) { checkReal(i.first, H, adj, real); } } } double solve(int N, int M, int K, int H, std::vector<int> x, std::vector<int> y, std::vector<int> c, std::vector<int> arr) { vector<vector<pair<int, int>>> adj(N); for (int i = 0; i < M; i++) { adj[x[i]].push_back({y[i], c[i]}); adj[y[i]].push_back({x[i], c[i]}); } // find "real" nodes vector<bool> real(N, false); checkReal(0, H, adj, real); if (!real[H]) return -1; // real[H] = false; // start djikstra's from H ld mn = INF; vector<vector<ld>> dist(N, vector<ld>(K + 1, INF)); dist[H][0] = 0; priority_queue<T, vector<T>, greater<T>> pq; pq.push({0, 0, H}); while (!pq.empty()) { const auto [cdist, k, node] = pq.top(); pq.pop(); if (cdist > dist[node][k]) continue; if ((arr[node] == 0 || node == 0) && real[node]) { mn = min(mn, cdist); continue; } if (cdist != dist[node][k]) continue; for (const pair<int, int> &i : adj[node]) { // if (i.first == H) continue; if (!real[i.first]) continue; if (cdist + divByPow2(i.second, k) < dist[i.first][k]) { dist[i.first][k] = cdist + divByPow2(i.second, k); pq.push({dist[i.first][k], k, i.first}); } // power-up 2 if (arr[i.first] == 2 && cdist + divByPow2(i.second, k + 1) < dist[i.first][k+1] && k < K && node != H) { dist[i.first][k+1] = cdist + divByPow2(i.second, k + 1); pq.push({dist[i.first][k+1], k + 1, i.first}); } } } return mn == INF ? -1 : mn; }
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