Submission #1157113

#	Time	Username	Problem	Language	Result	Execution time	Memory
1157113		MPG	Bitaro’s Party (JOI18_bitaro)	C++20	7 / 100	1713 ms	539648 KiB

bitaro

//#pragma GCC optomize("Ofast")
#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("O3")
//#pragma GCC target("avx2")
//#pragma GCC target("sse,sse2,sse4.1,sse4.2") 



#include <bits/stdc++.h>
using namespace std;
typedef long long                           ll;
#define                                     max_heap priority_queue<pair <ll, pair <ll, ll>>>
#define                                     min_heap priority_queue<pair <ll, ll>, vector<pair <ll, ll>>, greater<pair <ll, ll>>>
//#define                                     min_heap priority_queue<ll, vector<ll>, greater<ll>>
#define                                     sariE cin.tie(NULL); cout.tie(NULL); ios_base::sync_with_stdio(false);
#define                                     filE freopen("in.txt", "r", stdin); freopen("out1.txt", "w", stdout); 
#define                                     endl '\n'
#define                                     md(a) (a % mod + mod) % mod
#define pb push_back
//cout << vectorprecision(5) << fixed << f;
//hash prime = 769
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());


ll const maxn = 2e5 + 123;
ll const inf = 2e18;
ll const loG = 23;
ll const mod = 1e9 + 7;
//ll const mod = 998244353;
ll const sq = 500;
ll power(ll a, ll b, ll mod){if(b==0)return 1;if(b==1)return a;ll x = power(a, b / 2, mod);return (((x * x) % mod) * (b % 2 ? a : 1)) % mod;}


ll n, m, q, mx[maxn], dp[maxn];
vector <ll> g[maxn];
vector <pair <ll, ll>> tool[maxn];
bool mark[maxn];



void Solve(){

cin >> n >> m >> q;
for (int i = 1; i < m + 1; i++){
    ll a, b; cin >> a >> b;
    g[b].pb(a);
}
tool[1].pb({0, 1});
for (int i = 1; i < n + 1; i++)
    mx[i] = -inf;
for (int i = 2; i < n + 1; i++){
    vector <ll> tmp; tmp.clear();
    for (ll u : g[i]){
        for (auto p : tool[u]){
            mx[p.second] = max(mx[p.second], p.first + 1);
            if (!mark[p.second]){
                tmp.pb(p.second);
                mark[p.second] = 1;
            }
        }
    }
    vector <pair <ll, ll>> st; st.clear();
    for (ll x : tmp){
        st.pb({mx[x], x});
        mark[x] = 0;
        mx[x] = -inf;
    }
    st.pb({0, i});
    //cout << i << ' ' << st.size() << endl;
    sort(st.begin(), st.end());
    ll cnt = 0;
    for (int j = st.size() - 1; (j > -1 && cnt <= sq); j--){
        cnt++;
        tool[i].pb({st[j].first, st[j].second});
    }
}

// for (int i = 2; i < n + 1; i++){
//     cout << i << " :: " << endl;
//     for (auto p : tool[i])
//         cout << p.first << ' ' << p.second << endl;
// }




while (q--){
    ll v, t; cin >> v >> t;
    vector <ll> tmp; tmp.clear();
    for (int i = 1; i < t + 1; i++){
        ll x; cin >> x;
        tmp.pb(x);
        mark[x] = 1;
    }
    if (t >= sq){
        for (int i = 1; i < v + 1; i++){
            dp[i] = -inf;
            if (!mark[i])
                dp[i] = 0;
            for (ll u : g[i])
                dp[i] = max(dp[i], dp[u] + 1);
        }
        cout << (dp[v] < 0 ? -1 : dp[v]) << endl;
    }
    else{
        ll ans = -inf;
        for (auto p : tool[v]){
            if (!mark[p.second])
                ans = max(ans, p.first);
        }
        cout << (ans < 0 ? -1 : ans) << endl;
    }
    for (ll x : tmp)
        mark[x] = 0;
}




}





int main(){
sariE;// filE;



int test = 1;
//cin >> test;
while (test--) Solve();
return 0;
}

• Subtask 1: 7 / 7
• Subtask 2: 0 / 7
• Subtask 3: 0 / 86