Submission #1156583

#	Time	Username	Problem	Language	Result	Execution time	Memory
1156583		guagua0407	Spy 3 (JOI24_spy3)	C++20	0 / 100	1044 ms	818600 KiB

Aoi

//#include "grader.cpp"
#include "Aoi.h"
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define pii pair<int,int>
#define f first
#define s second
#define all(x) x.begin(),x.end()
#define _ ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
namespace {

int variable_example = 0;

int function_example(int a, int b) { return a + b; }

}  // namespace

std::string aoi(int N, int M, int Q, int K, std::vector<int> A,
                std::vector<int> B, std::vector<long long> C,
                std::vector<int> T, std::vector<int> X) {
    string S;
    for(int i=0;i<K;i++){
        for(int j=0;j<40;j++){
            if(C[X[i]]&(1ll<<i)) S+="1";
            else S+="0";
        }
    }
    return S;
}

Bitaro

//#include "grader.cpp"
#include "Bitaro.h"
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define pii pair<int,int>
#define f first
#define s second
#define all(x) x.begin(),x.end()
#define _ ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
namespace {

const ll inf=(ll)1e18;

}  // namespace

void bitaro(int n, int m, int q, int K, std::vector<int> A, std::vector<int> B,
            std::vector<long long> C, std::vector<int> T, std::vector<int> X,
            std::string S) {
    for(int i=0;i<K;i++){
        for(int j=0;j<40;j++){
            if(S[j+i*40]=='1') C[i]+=(1ll<<j);
        }
    }
    vector<vector<pair<int,pair<int,ll>>>> adj(n);
    for(int i=0;i<m;i++){
        adj[A[i]].push_back({B[i],{i,C[i]}});
        adj[B[i]].push_back({A[i],{i,C[i]}});
    }
    priority_queue<pair<ll,int>,vector<pair<ll,int>>,greater<pair<ll,int>>> pq;
    vector<ll> d(n,inf);
    vector<pair<int,int>> prv(n,{-1,-1});
    d[0]=0;
    pq.push({0,0});
    while(!pq.empty()){
        auto v=pq.top();
        pq.pop();
        if(v.f!=d[v.s]) continue;
        for(auto u:adj[v.s]){
            if(d[v.s]+u.s.s<d[u.f]){
                prv[u.f]={v.s,u.s.f};
                d[u.f]=d[v.s]+u.s.s;
                pq.push({d[u.f],u.f});
            }
        }
    }
    for(int i=0;i<q;i++){
        vector<int> res;
        int cur=T[i];
        while(cur!=0){
            res.push_back(prv[cur].s);
            cur=prv[cur].f;
        }
        reverse(all(res));
        answer(res);
    }
}

• Subtask 1: 0 / 100