Submission #1155845

#TimeUsernameProblemLanguageResultExecution timeMemory
1155845adiyerFlooding Wall (BOI24_wall)C++20
44 / 100
485 ms1114112 KiB
#include <bits/stdc++.h> #define all(x) x.begin(), x.end() #define len(s) (ll) s.size() #define pb push_back #define F first #define S second using namespace std; typedef long long ll; const int N = 1e4 + 3; const int P = 31; const int mod = 1e9 + 7; const ll inf = 1e18; int n, sz, res, x, i, j, l, r, cur1, cur2; int a[N], b[N], ia[N], ib[N], p[2 * N], s[2 * N], val[2 * N]; vector < int > c; map < int, int > mp; signed main(){ ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); cin >> n; for(i = 1; i <= n; i++) cin >> a[i], c.pb(a[i]); for(i = 1; i <= n; i++) cin >> b[i], c.pb(b[i]); sort(all(c)); for(int vl : c) if(!mp[vl]) mp[vl] = ++sz, val[sz] = vl; for(i = 1; i <= n; i++) ia[i] = a[i], a[i] = mp[a[i]], ib[i] = b[i], b[i] = mp[b[i]]; int dp[N][sz + 5][2] = {}; for(int fg = 0; fg < 2; fg++){ if(fg){ reverse(a + 1, a + n + 1); reverse(b + 1, b + n + 1); } dp[0][0][fg] = 1; for(x = 0; x <= sz; x++) p[x] = 1; for(i = 1; i <= n; i++){ for(x = sz; x >= 0; x--){ int &y = dp[i][x][fg]; if(a[i] > x && b[i] > x) y = 0; else if(a[i] > x || b[i] > x){ if(a[i] == x || b[i] == x) y = p[x]; else y = dp[i - 1][x][fg]; } else{ if(a[i] == x && b[i] == x) y = p[x] * 2; else if(a[i] == x || b[i] == x) y = p[x] + dp[i - 1][x][fg]; else y = dp[i - 1][x][fg] * 2; } y %= mod; } for(x = 0; x <= sz; x++){ if(x) p[x] = (p[x - 1] + dp[i][x][fg]) % mod; else p[x] = dp[i][x][fg]; } } if(fg){ reverse(a + 1, a + n + 1); reverse(b + 1, b + n + 1); } } for(i = 2; i < n; i++){ l = i - 1, r = n - i, cur1 = 0, cur2 = 0; for(x = sz; x >= 0; x--){ s[x] = (s[x + 1] + dp[r][x][1]) % mod; } for(x = 0; x <= sz; x++){ res += (dp[l][x][0] * 1ll * cur1) % mod, res %= mod; res += (dp[l][x][0] * 1ll * cur2) % mod, res %= mod; if(x > a[i]) res += ((dp[l][x][0] * 1ll * s[x]) % mod * 1ll * (val[x] - ia[i])) % mod, res %= mod, cur1 += (dp[r][x][1] * 1ll * (val[x] - ia[i])) % mod, cur1 %= mod; if(x > b[i]) res += ((dp[l][x][0] * 1ll * s[x]) % mod * 1ll * (val[x] - ib[i])) % mod, res %= mod, cur2 += (dp[r][x][1] * 1ll * (val[x] - ib[i])) % mod, cur2 %= mod; } } cout << res; }
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