Submission #1154471

#	Time	Username	Problem	Language	Result	Execution time	Memory
1154471		burgerguy	Cyberland (APIO23_cyberland)	C++20	97 / 100	90 ms	70724 KiB

cyberland

#include <bits/stdc++.h>

using namespace std;
using ll = long long;

class DisjointUnionSets {
    vector<ll> rank, parent;

public:
    DisjointUnionSets(ll n) {
        rank.resize(n, 0);
        parent.resize(n);

        for (ll i = 0; i < n; i++) {
            parent[i] = i;
        }
    }

    ll find(ll i) {
        ll root = parent[i];

        if (parent[root] != root) {
            return parent[i] = find(root);
        }

        return root;
    }

    void unionSets(int x, int y) {
        ll xRoot = find(x);
        ll yRoot = find(y);

        if (xRoot == yRoot) return;

        if (rank[xRoot] < rank[yRoot]) {
            parent[xRoot] = yRoot;
        }
        else if (rank[yRoot] < rank[xRoot]) {
            parent[yRoot] = xRoot;
        }
        else {
            parent[yRoot] = xRoot;
            rank[xRoot]++;
        }
    }
};

double solve(int N, int M, int K, int H, std::vector<int> x, std::vector<int> y, std::vector<int> c, std::vector<int> arr) {
    vector<vector<pair<ll,ll>>> adj(N);

    DisjointUnionSets dsu(N);

    for (int i = 0; i < M; ++i) {
        if (x[i] != H && y[i] != H) dsu.unionSets(x[i], y[i]);

        adj[x[i]].emplace_back(y[i],c[i]);
        adj[y[i]].emplace_back(x[i], c[i]);
    }


    K = min(K, 60);
    vector<vector<double>> dist(N + 10, vector<double>(K + 10, 1e18));

    priority_queue<tuple<double, ll, ll>, vector<tuple<double, ll, ll>>, greater<>> q;

    q.emplace(0, 0, H);
    dist[H][0] = 0;

    while(!q.empty()) {
        double curDistance = get<0>(q.top());
        ll curK = get<1>(q.top());
        ll curNode = get<2>(q.top());

        q.pop();

        if(dist[curNode][curK] < curDistance) continue;

        if((arr[curNode] == 0 || curNode == 0)) return curDistance;

        for(auto [newNode, distance] : adj[curNode]) {
            if (dsu.find(newNode) != dsu.find(0)) continue;
            double newDistance = curDistance + (double(distance)/pow(2, curK));

            if(newDistance < dist[newNode][curK]) {
                dist[newNode][curK] = newDistance;
                q.emplace(newDistance, curK, newNode);
            }

            if(arr[curNode] == 2) {
                if(curK < K) {
                    double betterDistance = curDistance + (double(distance)/pow(2, curK + 1));

                    if(betterDistance < dist[newNode][curK + 1]) {
                        dist[newNode][curK + 1] = betterDistance;
                        q.emplace(betterDistance, curK + 1, newNode);
                    }
                }
            }
        }
    }

    return -1;
}

• Subtask 1: 5 / 5
• Subtask 2: 8 / 8
• Subtask 3: 13 / 13
• Subtask 4: 19 / 19
• Subtask 5: 7 / 7
• Subtask 6: 16 / 16
• Subtask 7: 29 / 29
• Subtask 8: 0 / 3