#include<bits/stdc++.h>
#define pb push_back
#define mp make_pair
#define int long long
#define vi vector<int>
#define vvi vector<vector<int>>
#define pii pair<int, int>
#define vpii vector<pair<int, int>>
#define vc vector<char>
#define vb vector<bool>
#define mii map<int,int>
#define f0r(i,n) for(int i=0;i<n;i++)
#define FOR(i,k,n) for(int i=k;i<n;i++)
#define all(v) (v).begin(),(v).end()
#define rall(v) (v).rbegin(),(v).rend()
#define in(a) int a; cin>>a
#define in2(a,b) int a,b; cin>>a>>b
#define in3(a,b,c) int a,b,c; cin>>a>>b>>c
#define in4(a,b,c,d) int a,b,c,d; cin>>a>>b>>c>>d
#define vin(v,n); vi v(n); f0r(i,n){cin>>v[i];}
#define out(a) cout<<a<<'\n'
#define out2(a,b) cout<<a<<' '<<b<<'\n'
#define out3(a,b,c) cout<<a<<' '<<b<<' '<<c<<'\n'
#define out4(a,b,c,d) cout<<a<<' '<<b<<' '<<c<<' '<<d<<'\n'
#define vout(v) for(auto u : v){cout<<u<<' ';} cout<<'\n'
#define dout(a) cout<<a<<' '<<#a<<'\n'
#define dout2(a,b) cout<<a<<' '<<#a<<' '<<b<<' '<<#b<<'\n'
#define yn(x); if(x){cout<<"YES"<<'\n';}else{cout<<"NO"<<'\n';}
const int leg = 1e9 + 7;
const int mod = 998244353;
using namespace std;
const int mxn = 1e5 + 5;
pii tree[mxn * 4];
int n;
int v[mxn];
void update(int k, int x){
k += n;
tree[k] = {x, k-n};
for(k/=2; k>=1; k/=2){
tree[k] = min(tree[k*2], tree[k*2+1]);
}
}
pii quer(int l, int r){
l += n; r += n;
pii ret = {4e18, 0};
while(l <= r){
if(l % 2 == 1)ret = min(ret, tree[l++]);
if(r % 2 == 0)ret = min(ret, tree[r--]);
l/=2; r/=2;
}
return ret;
}
int nxt[mxn];
map<int, vi>m;
int solve(int l, int r){
//dout2(l,r);
if(l > r)return 0;
pii mn = quer(l, r);
int cur = mn.second;
int lef = mn.second;
vi splits;
int ans=1;
splits.pb(l-1);
splits.pb(cur);
while(nxt[cur] <= r && nxt[cur] != -1){
cur = nxt[cur];
splits.pb(cur);
}
splits.pb(r + 1);
//vout(splits);
f0r(i,splits.size() - 1){
ans += solve(splits[i] + 1, splits[i+1] - 1);
}
return ans;
}
signed main(){
ios::sync_with_stdio(false);
cin.tie(NULL);
//ifstream cin(".in");
//ofstream cout(".out");
cin>>n;
f0r(i,n)cin>>v[i];
f0r(i,n){
update(i, v[i]);
}
f0r(i,n)nxt[i] = -1;
f0r(i,n){
if(m[v[i]].size() != 0){
nxt[m[v[i]][m[v[i]].size() - 1]] = i;
}
m[v[i]].pb(i);
}
//f0r(i,n)cout<<nxt[i]<<' ';
//cout<<'\n';
int ans = solve(0, n-1);
out(ans);
}
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