제출 #1152811

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1152811		gyg	Rectangles (IOI19_rect)	C++20	27 / 100	171 ms	260356 KiB

rect

#pragma GCC optimize("O3", "unroll-loops")
#pragma GCC target("avx2")
#include "rect.h"
#include <bits/stdc++.h>
using namespace std;
#define sig signed
#define int long long
#define arr array 
#define vec vector
#define pii pair<int, int>
#define fir first 
#define sec second
const int N = 200 + 5, M = 200 + 5;

int n, m;
arr<arr<int, M>, N> a;

arr<arr<arr<int, M>, M>, N> up, dwn, vld, fr;
void prcmp() {
	for (int j = 1; j <= m; j++) {
		vec<int> x;
		for (int i = n; i >= 1; i--) {
			while (x.size() && a[x.back()][j] <= a[i][j]) {
				up[x.back()][j][j] = i;
				x.pop_back();
			}
			x.push_back(i);
		}
		while (x.size()) {
			up[x.back()][j][j] = 0;
			x.pop_back();
		}
	}

	for (int j = 1; j <= m; j++) {
		vec<int> x;
		for (int i = 1; i <= n; i++) {
			while (x.size() && a[x.back()][j] <= a[i][j]) {
				dwn[x.back()][j][j] = i;
				x.pop_back();
			}
			x.push_back(i);
		}
		while (x.size()) {
			dwn[x.back()][j][j] = n + 1;
			x.pop_back();
		}
	}

	for (int i = 1; i <= n; i++) {
		for (int l = 1; l <= m; l++) {
			int mx = -1;
			for (int r = l; r <= m; r++) {
				if (r != l) {
					up[i][l][r] = max(up[i][l][r - 1], up[i][r][r]);
					dwn[i][l][r] = min(dwn[i][l][r - 1], dwn[i][r][r]);
				}
				
				mx = max(mx, a[i][r]);
				if (l != 1 && r != m) vld[i][l][r] = (mx < min(a[i][l - 1], a[i][r + 1]));
			}
		}
	}

	for (int i = n; i >= 1; i--) {
		for (int l = 1; l <= m; l++) {
			for (int r = l; r <= m; r++) {
				fr[i][l][r] = n + 1;

				for (int j = i + 1; j <= n; j++) 
					if (!vld[j][l][r]) { fr[i][l][r] = j; break; }

				// cout << i << " " << l << " " << r << ": " << dwn[i][l][r] << " " << fr[i][l][r] << '\n';
			}
		}
	}
}

int cmp() {
	int ans = 0;
	for (int i = 1; i <= n; i++) {
		for (int l = 1; l <= m; l++) {
			for (int r = l; r <= m; r++) {
				int j = min({dwn[i][l][r], fr[i][l][r], n});
				if (j < i + 2) continue;

				// cout << i << " " << l << " " << r << ": " << i + 2 << " to " << j << '\n';

				for (int k = i + 2; k <= j; k++)
					ans += (up[k][l][r] <= i);
			}
		}
	}
	return ans;
}

int count_rectangles(vec<vec<sig>> _a) {
	n = _a.size(), m = _a[0].size();
	for (int i = 1; i <= n; i++)
		for (int j = 1; j <= m; j++)
			a[i][j] = _a[i - 1][j - 1];

	prcmp();
	return cmp();
}

• Subtask 1: 8 / 8
• Subtask 2: 7 / 7
• Subtask 3: 12 / 12
• Subtask 4: 0 / 22
• Subtask 5: 0 / 10
• Subtask 6: 0 / 13
• Subtask 7: 0 / 28