Submission #1151356

#TimeUsernameProblemLanguageResultExecution timeMemory
1151356koukirocksGrowing Vegetable is Fun 3 (JOI19_ho_t3)C++20
100 / 100
56 ms109168 KiB
#include <bits/stdc++.h> #define speed ios_base::sync_with_stdio(0); cin.tie(0) #define all(x) (x).begin(),(x).end() #define F first #define S second //#pragma GCC optimize("O3,unroll-loops") //#pragma GCC target("avx,avx2") //#pragma GCC target("popcnt") using namespace std; typedef long long ll; typedef unsigned long long ull; typedef double db; typedef long double ldb; typedef pair<int,int> pii; typedef pair<ll,ll> pll; const ll MAX=2e5+10,P=1e9+7; const ll INF=0x3f3f3f3f,oo=0x3f3f3f3f3f3f3f3f; const ldb eps=1e-6; const ldb PI=acos(-1.0); const int dir[4][2]={{0,1},{0,-1},{1,0},{-1,0}}; template<typename T> using vvector = vector<vector<T>>; int dp[210][210][210][3]; int p[3][410]; int pre[3][410]; int main() { speed; int n; cin>>n; string s; cin>>s; s='-'+s; int cnt[3]={0,0,0}; pre[0][0]=pre[1][0]=pre[2][0]=0; for (int i=1;i<=n;i++) { for (int k=0;k<3;k++) pre[k][i]=pre[k][i-1]; if (s[i]=='R') { cnt[0]++; p[0][cnt[0]]=i; pre[0][i]++; } else if (s[i]=='G') { cnt[1]++; p[1][cnt[1]]=i; pre[1][i]++; } else if (s[i]=='Y') { cnt[2]++; p[2][cnt[2]]=i; pre[2][i]++; } } if (cnt[0]>(n+1)/2 or cnt[1]>(n+1)/2 or cnt[2]>(n+1)/2) { cout<<"-1\n"; return 0; } memset(dp,0x3f,sizeof(dp)); dp[0][0][0][0]=0; dp[0][0][0][1]=0; dp[0][0][0][2]=0; for (int i=0;i<=cnt[0];i++) { for (int j=0;j<=cnt[1];j++) { for (int k=0;k<=cnt[2];k++) { if (i!=0) dp[i][j][k][0]=min(dp[i-1][j][k][1],dp[i-1][j][k][2])+abs(pre[1][p[0][i]]-j)+abs(pre[2][p[0][i]]-k); if (j!=0) dp[i][j][k][1]=min(dp[i][j-1][k][0],dp[i][j-1][k][2])+abs(pre[0][p[1][j]]-i)+abs(pre[2][p[1][j]]-k); if (k!=0) dp[i][j][k][2]=min(dp[i][j][k-1][1],dp[i][j][k-1][0])+abs(pre[1][p[2][k]]-j)+abs(pre[0][p[2][k]]-i); // cout<<i<<" "<<j<<" "<<k<<" ijk\n"; // cout<<p[0][i]<<" "<<p[1][j]<<" "<<p[2][k]<<"\n"; // cout<<dp[i][j][k][0]<<"\n"<<dp[i][j][k][1]<<"\n"<<dp[i][j][k][2]<<"\n"; } } } cout<<min({dp[cnt[0]][cnt[1]][cnt[2]][0],dp[cnt[0]][cnt[1]][cnt[2]][1],dp[cnt[0]][cnt[1]][cnt[2]][2]})/2<<"\n"; return 0; }
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