Submission #1150143

#	Time	Username	Problem	Language	Result	Execution time	Memory
1150143		monkey133	Povjerenstvo (COI22_povjerenstvo)	C++20	21 / 100	433 ms	49080 KiB

Main

#include <bits/stdc++.h>
//#include "includeall.h"
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
#define endl '\n'
#define f first
#define s second
#define pb push_back
#define mp make_pair
#define lb lower_bound
#define ub upper_bound
#define input(x) scanf("%lld", &x);
#define input2(x, y) scanf("%lld%lld", &x, &y);
#define input3(x, y, z) scanf("%lld%lld%lld", &x, &y, &z);
#define input4(x, y, z, a) scanf("%lld%lld%lld%lld", &x, &y, &z, &a);
#define print(x, y) printf("%lld%c", x, y);
#define show(x) cerr << #x << " is " << x << endl;
#define show2(x,y) cerr << #x << " is " << x << " " << #y << " is " << y << endl;
#define show3(x,y,z) cerr << #x << " is " << x << " " << #y << " is " << y << " " << #z << " is " << z << endl;
#define all(x) x.begin(), x.end()
#define discretize(x) sort(x.begin(), x.end()); x.erase(unique(x.begin(), x.end()), x.end());
#define FOR(i, x, n) for (ll i =x; i<=n; ++i) 
#define RFOR(i, x, n) for (ll i =x; i>=n; --i) 
#pragma GCC optimize("O3","unroll-loops")
using namespace std;
mt19937_64 rnd(chrono::steady_clock::now().time_since_epoch().count());
//using namespace __gnu_pbds;
//#define ordered_set tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update>
//#define ordered_multiset tree<int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update>
typedef long long ll;
typedef long double ld;
typedef pair<ld, ll> pd;
typedef pair<string, ll> psl;
typedef pair<ll, ll> pi;
typedef pair<pi, ll> pii;
typedef pair<pi, pi> piii;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

vector<ll> adj[500005];
ll ans[500005];

void dfs(ll x)
{
	for (ll u: adj[x]) {if (ans[u]==-1) {ans[u] = ans[x]^1; dfs(u);}}
}

int main()
{
	ll n, m;
	cin >> n >> m;
	fill(ans, ans + n + 1, -1);
	for (ll i=0; i<m; ++i)
	{
		ll u, v;
		cin >> u >> v;
		adj[u].pb(v);
		adj[v].pb(u);
	}
	for (ll i=1; i<=n; ++i) if (ans[i]==-1) ans[i] = 0, dfs(i);
	vector<ll> res, res2;
	for (ll i=1; i<=n; ++i) {if (ans[i]==0) res.pb(i); else res2.pb(i);}
	if (res.size() < res2.size()) swap(res, res2);
	cout << res.size() << endl;
	for (ll u: res) cout << u << ' ';
	
	
	return 0;
}

• Subtask 1: 0 / 13
• Subtask 2: 21 / 21
• Subtask 3: 0 / 33
• Subtask 4: 0 / 33