제출 #1147963

#제출 시각아이디문제언어결과실행 시간메모리
1147963monkey133The Kingdom of JOIOI (JOI17_joioi)C++20
100 / 100
1321 ms31824 KiB
#include <bits/stdc++.h> //#include "includeall.h" //#include <ext/pb_ds/assoc_container.hpp> //#include <ext/pb_ds/tree_policy.hpp> #define endl '\n' #define f first #define s second #define pb push_back #define mp make_pair #define lb lower_bound #define ub upper_bound #define input(x) scanf("%lld", &x); #define input2(x, y) scanf("%lld%lld", &x, &y); #define input3(x, y, z) scanf("%lld%lld%lld", &x, &y, &z); #define input4(x, y, z, a) scanf("%lld%lld%lld%lld", &x, &y, &z, &a); #define print(x, y) printf("%lld%c", x, y); #define show(x) cerr << #x << " is " << x << endl; #define show2(x,y) cerr << #x << " is " << x << " " << #y << " is " << y << endl; #define show3(x,y,z) cerr << #x << " is " << x << " " << #y << " is " << y << " " << #z << " is " << z << endl; #define all(x) x.begin(), x.end() #define discretize(x) sort(x.begin(), x.end()); x.erase(unique(x.begin(), x.end()), x.end()); #define FOR(i, x, n) for (ll i =x; i<=n; ++i) #define RFOR(i, x, n) for (ll i =x; i>=n; --i) #pragma GCC optimize("O3","unroll-loops") using namespace std; mt19937_64 rnd(chrono::steady_clock::now().time_since_epoch().count()); //using namespace __gnu_pbds; //#define ordered_set tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> //#define ordered_multiset tree<int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update> typedef long long ll; typedef long double ld; typedef pair<ld, ll> pd; typedef pair<string, ll> psl; typedef pair<ll, ll> pi; typedef pair<ll, pi> pii; typedef pair<pi, pi> piii; mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); ll h,w; ll a[2005][2005]; ll minn = LLONG_MAX, maxx = LLONG_MIN; bool check(ll x) { ll dist = -1; for (ll i=0; i<h; ++i) { for (ll j=0; j<w; ++j) if (maxx - a[i][j] > x) dist = max(dist, j); for (ll j=0; j<w; ++j) if (a[i][j] - minn > x && j <= dist) return 0; } return 1; } void reflectx() { for (ll i=0; i<h/2; ++i) for (ll j=0; j<w; ++j) swap(a[i][j], a[h-1-i][j]); } void reflecty() { for (ll i=0; i<h; ++i) for (ll j=0; j<w/2; ++j) swap(a[i][j], a[i][w-1-j]); } ll solve() { ll lo = 0, hi = maxx - minn; while (lo!=hi) { ll mid = (lo + hi) >> 1; if (check(mid)) hi = mid; else lo = mid + 1; } return lo; } int main() { cin >> h >> w; for (ll i=0; i<h; ++i) for (ll j=0; j<w; ++j) cin >> a[i][j]; for (ll i=0; i<h; ++i) for (ll j=0; j<w; ++j) {minn = min(minn, a[i][j]); maxx = max(maxx, a[i][j]);} ll ans = solve(); reflectx(); ans = min(ans, solve()); reflecty(); ans = min(ans, solve()); reflectx(); ans = min(ans, solve()); cout << ans << endl; return 0; }
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