#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const ll INF = 1e18+7;
const ll MOD = 998244353;
typedef pair<ll,ll> ii;
#define iii pair<ii,ll>
#define f(i,a,b) for(ll i = a;i < b;i++)
#define pb push_back
#define vll vector<ll>
#define F first
#define S second
#define all(x) (x).begin(), (x).end()
///I hope I will get uprating and don't make mistakes
///I will never stop programming
///sqrt(-1) Love C++
///Please don't hack me
///@TheofanisOrfanou Theo830
///Think different approaches (bs,dp,greedy,graphs,shortest paths,mst)
///Stay Calm
///Look for special cases
///Beware of overflow and array bounds
///Think the problem backwards
///Training
ll num = 0;
ll dp[2005];
ll arr[2005];
ll n,a,b;
ll po;
ll solve(ll idx){
if(idx == n){
return 0;
}
if(dp[idx] != -1){
return dp[idx];
}
ll ans = INF;
ll sum = 0;
f(k,idx,n){
sum += arr[k];
ll val = sum | num;
val -= num;
if(val < po){
ans = min(ans,1 + solve(k+1));
}
}
return dp[idx] = ans;
}
int main(void){
ios_base::sync_with_stdio(0);
cin.tie(0);
cin>>n>>a>>b;
f(i,0,n){
cin>>arr[i];
}
for(ll i = 60;i >= 0;i--){
po = (1LL<<i);
memset(dp,-1,sizeof dp);
if(solve(0) > b){
num += po;
}
}
cout<<num<<"\n";
}
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