Submission #1143791

#TimeUsernameProblemLanguageResultExecution timeMemory
1143791monkey133Jail (JOI22_jail)C++20
100 / 100
1551 ms522084 KiB
#include <bits/stdc++.h> //#include "includeall.h" //#include <ext/pb_ds/assoc_container.hpp> //#include <ext/pb_ds/tree_policy.hpp> #define endl '\n' #define f first #define s second #define pb push_back #define mp make_pair #define lb lower_bound #define ub upper_bound #define input(x) scanf("%lld", &x); #define input2(x, y) scanf("%lld%lld", &x, &y); #define input3(x, y, z) scanf("%lld%lld%lld", &x, &y, &z); #define input4(x, y, z, a) scanf("%lld%lld%lld%lld", &x, &y, &z, &a); #define print(x, y) printf("%lld%c", x, y); #define show(x) cerr << #x << " is " << x << endl; #define show2(x,y) cerr << #x << " is " << x << " " << #y << " is " << y << endl; #define show3(x,y,z) cerr << #x << " is " << x << " " << #y << " is " << y << " " << #z << " is " << z << endl; #define all(x) x.begin(), x.end() #define discretize(x) sort(x.begin(), x.end()); x.erase(unique(x.begin(), x.end()), x.end()); #define FOR(i, x, n) for (ll i =x; i<=n; ++i) #define RFOR(i, x, n) for (ll i =x; i>=n; --i) using namespace std; mt19937_64 rnd(chrono::steady_clock::now().time_since_epoch().count()); //using namespace __gnu_pbds; //#define ordered_set tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> //#define ordered_multiset tree<int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update> typedef long long ll; typedef long double ld; typedef pair<ld, ll> pd; typedef pair<string, ll> psl; typedef pair<ll, ll> pi; typedef pair<ll, pi> pii; typedef pair<pi, pi> piii; mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); ll n, m, lab; vector<ll> adj[5000005], adj2[5000005]; ll st[5000005],fi[5000005]; ll twok[500005][25], id1[500005][25], id2[500005][25], dep[5000005], status[5000005]; ll kpar(ll x, ll k) { for (ll i=0; i<17; ++i) if ((1LL << i)&k) x = twok[x][i]; return x; } ll lca(ll x, ll y) { if (x==y) return x; if (dep[x] < dep[y]) swap(x, y); x = kpar(x, dep[x] - dep[y]); if (x==y) return x; for (ll i=16; i>=0; --i) { if (twok[x][i]==0 || twok[y][i]==0 || twok[x][i]==twok[y][i]) continue; x = twok[x][i], y = twok[y][i]; } return twok[x][0]; } void dfs(ll x = 1, ll p = -1) { for (ll k=1; k<17; ++k) { twok[x][k] = twok[twok[x][k-1]][k-1]; id1[x][k] = ++lab; id2[x][k] = ++lab; // start : go up if (id1[x][k-1] > 0) adj2[id1[x][k-1]].pb(id1[x][k]); if (id1[twok[x][k-1]][k-1] > 0) adj2[id1[twok[x][k-1]][k-1]].pb(id1[x][k]); // end : go down if (id2[x][k-1] > 0) adj2[id2[x][k]].pb(id2[x][k-1]); if (id2[twok[x][k-1]][k-1] > 0) adj2[id2[x][k]].pb(id2[twok[x][k-1]][k-1]); } for (ll u: adj[x]) if (u!=p) { dep[u] = dep[x] + 1; twok[u][0] = x; dfs(u, x); } } void add_dir(ll from , ll to, ll idx) { ll k = dep[from] - dep[to] + 1; ll now = from; for (ll i=16; i>=0; --i) if ((1LL << i) & k) { if (id1[now][i]) adj2[id1[now][i]].pb(idx); now = twok[now][i]; } } void add_rev(ll from , ll to, ll idx) { ll k = dep[from] - dep[to] + 1; ll now = from; for (ll i=16; i>=0; --i) if ((1LL << i) & k) { if (id2[now][i]) adj2[idx].pb(id2[now][i]); now = twok[now][i]; } } bool fail = false; void topo(ll node) { if (status[node]==2) return; if (status[node]==1) {fail = true; return;} status[node]=1; for (ll x: adj2[node]) { topo(x); if (fail) break; } status[node]=2; } void solve() { cin >> n; for (ll i=0; i<n-1; ++i) { ll u, v; cin >> u >> v; adj[u].pb(v); adj[v].pb(u); } cin >> m; lab = m; for (ll i=1; i<=m; ++i) { cin >> st[i] >> fi[i]; id1[st[i]][0] = i; id2[fi[i]][0] = i; } // decompose every path into log(n) segment + twok decomposition dfs(); if (lab >= 5000000) cout << 0 << endl; // add edges for (ll i=1; i<=m; ++i) { ll lc = lca(st[i], fi[i]); // connect to other st[i] // *excluding st[i] -> st[i] to prevent self-loop if (st[i]==lc) add_dir(fi[i], kpar(fi[i], dep[fi[i]] - dep[st[i]]-1), i); else add_dir(twok[st[i]][0], lc, i), add_dir(fi[i], lc, i); // connect to other fi[i] if (fi[i]==lc) add_rev(st[i], kpar(st[i], dep[st[i]] - dep[fi[i]]-1), i); else add_rev(st[i], lc, i), add_rev(twok[fi[i]][0], lc, i); } for (ll i=1; i<=m; ++i) topo(i); if (fail) cout << "No\n"; else cout << "Yes\n"; for (ll i=1; i<=n; ++i) adj[i].clear(), dep[i] = 0; for (ll i=1; i<=lab; ++i) adj2[i].clear(), status[i] = 0; for (ll i=1; i<=n; ++i) for (ll k=0; k<20; ++k) twok[i][k] = id1[i][k] = id2[i][k] = 0; fail = 0; } int main() { ll q; cin >> q; while (q--) solve(); return 0; }
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