제출 #114277

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
114277		dorijanlendvaj	무지개나라 (APIO17_rainbow)	C++14	0 / 100	3088 ms	29924 KiB

rainbow

#include "rainbow.h"
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#define x first
#define y second
#define pii pair<int,int>
#define pb push_back
#define eb emplace_back

using namespace std;
using namespace __gnu_pbds;
using ll=long long;

int dx[]={0,1,0,-1,1,1,-1,-1};
int dy[]={1,0,-1,0,1,-1,1,-1};
int n,m;
set<pii> s;
vector<pii> ou,prr;

void init(int R, int C, int sr, int sc, int M, char *S) {
	set<pii> pros;
	--sr;
	--sc;
	for (int i=0;i<M;++i)
	{
		//if (s.find({sr,sc})!=s.end()) s.erase({sr,sc});
		pros.insert({sr,sc});
		for (int k=0;k<8;++k) s.insert({sr+dx[k],sc+dy[k]});
		if (S[i]=='W') --sc;
		if (S[i]=='E') ++sc;
		if (S[i]=='N') --sr;
		if (S[i]=='S') ++sr;
	}
	pros.insert({sr,sc});
	for (auto a: pros) prr.pb(a);
	for (int k=0;k<8;++k) s.insert({sr+dx[k],sc+dy[k]});
	for (auto a: pros) if (s.find(a)!=s.end()) s.erase(a);
	for (auto a: s) ou.pb(a);
	//for (auto a: ou) cout<<a.x<<' '<<a.y<<endl;
}

int cnt,par[1000050];
bool pos[1000050];
vector<int> nap;
const int SZ=32987;
vector<pair<ll,int>> ht[SZ];
vector<int> sv;
//gp_hash_table<ll,int> nodes;

void change(ll i,int x)
{
	ll i1=i;
	i+=1872432922ll;
	i^=0x95872901245;
	i%=SZ;
	for (auto &a: ht[i]) if (a.x==i1)
	{
		a.y=x;
		return;
	}
	ht[i].pb({i1,x});
	sv.pb(i);
}

int get(ll i)
{
	ll i1=i;
	i+=1872432922ll;
	i^=0x95872901245;
	i%=SZ;
	for (auto a: ht[i]) if (a.x==i1) return a.y;
	return 0;
}

void clearHT()
{
	for (auto a: sv) ht[a].clear();
	sv.clear();
}

void add(int i)
{
	nap.pb(i);
	par[i]=i;
	pos[i]=1;
	++cnt;
}

int find(int i)
{
	if (!pos[i]) return -1;
	if (i==par[i]) return i;
	return par[i]=find(par[i]);
}

void merge(int a,int b)
{
	a=find(a);
	b=find(b);
	if (a==-1 || b==-1) return;
	if (a==b) return;
	par[a]=b;
	--cnt;
}

void clear()
{
	for (auto x: nap)
	{
		par[x]=-1;
		pos[x]=0;
	}
	nap.clear();
	cnt=0;
}

int colour(int ar, int ac, int br, int bc) {
    int x1=ar-1,x2=br-1,y1=ac-1,y2=bc-1;
    int cn=1;
    clearHT();
    for (auto a: ou) if (a.x>=x1 && a.x<=x2 && a.y>=y1 && a.y<=y2)
    {
    	change(a.x*200000ll+a.y,cn);
    	add(cn++);
    	for (int k=0;k<8;++k)
    	{
    		merge(get((a.x+dx[k])*200000ll+(a.y+dy[k])),cn-1);
		}
	}
	ll z=(y2-y1+1)*1ll*(x2-x1+1);
	if (cnt==0)
	{
		for (auto a: prr) if (a.x>=x1 && a.x<=x2 && a.y>=y1 && a.y<=y2) --z;
		if (z==0) return 0;
		return 1;
	}
	int ans=cnt;
	clear();
	return ans;
}
 

• Subtask 1: 0 / 11
• Subtask 2: 0 / 12
• Subtask 3: 0 / 24
• Subtask 4: 0 / 27
• Subtask 5: 0 / 26