제출 #114118

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
114118		fedoseevtimofey	Palembang Bridges (APIO15_bridge)	C++14	8 / 100	2041 ms	10972 KiB

bridge

#include <bits/stdc++.h>

#define int long long

using namespace std;

typedef long long ll;
typedef long double ld;

signed main() {
    ios_base::sync_with_stdio(false); cin.tie(0); cout.setf(ios::fixed); cout.precision(20);
    #ifdef LOCAL
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
    #endif
    int k, n;
    cin >> k >> n;
    vector <pair <int, int>> a;
    ll res = 0;
    vector <pair <int, int>> e;
    vector <int> c;
    ll cur = 0;
    int cnt1 = 0, cnt2 = 0;
    for (int i = 0; i < n; ++i) {
        char p, q;
        int x, y;
        cin >> p >> x >> q >> y;
        res += abs(x - y);
        if (x > y) swap(x, y);
        if (p != q) {
            e.push_back({x, -1});
            e.push_back({y, 1});
            a.emplace_back(x, y);
            cur += 2 * x;
            ++cnt1;
            ++res;
        }
        c.push_back(x);
        c.push_back(y);
    }
    sort(c.begin(), c.end());
    c.resize(unique(c.begin(), c.end()) - c.begin());
    sort(e.begin(), e.end());
    /*assert(k == 1);
    ll ans = cur + res;
    for (int i = 0; i < (int)e.size(); ++i) {
        if (i) {
            cur -= 2LL * cnt1 * (e[i].first - e[i - 1].first);
            cur += 2LL * cnt2 * (e[i].first - e[i - 1].first);
        }
        if (e[i].second == -1) --cnt1;
        else ++cnt2;
        ans = min(ans, res + cur);
    }
    cout << ans << '\n';*/
    ll ans = 1e18;
    for (auto x : c) {
        ll cur = res;
        for (auto p : a) {
            if (p.first <= x && x <= p.second) continue;
            cur += 2 * min(abs(p.first - x), abs(p.second - x));
        }
        ans = min(ans, cur);
    }
    cout << ans << '\n';
}

컴파일 시 표준 에러 (stderr) 메시지

bridge.cpp: In function 'int main()':
bridge.cpp:23:19: warning: unused variable 'cnt2' [-Wunused-variable]
     int cnt1 = 0, cnt2 = 0;
                   ^~~~

• Subtask 1: 8 / 8
• Subtask 2: 0 / 14
• Subtask 3: 0 / 9
• Subtask 4: 0 / 32
• Subtask 5: 0 / 37