제출 #1140809

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1140809		altern23	Art Exhibition (JOI18_art)	C++20	100 / 100	116 ms	12112 KiB

art

#include <bits/stdc++.h>
using namespace std;

#pragma GCC optimize ("O2")
#pragma GCC optimize ("unroll-loops")
 
#define ll long long
#define pii pair<ll,ll>
#define fi first
#define sec second
#define ld long double

ostream& operator << (ostream& os, pii x){
    os << "[";
    os << " " << x.fi << " " << x.sec;
    os << " ]";
 
    return os;
}

ostream& operator << (ostream& os, pair<pii, ll> x){
    os << "[";
    os << " " << x.fi << " " << x.sec;
    os << " ]";
 
    return os;
}

ostream& operator << (ostream& os, pair<ll, pii> x){
    os << "[";
    os << " " << x.fi << " " << x.sec;
    os << " ]";
 
    return os;
}

template <typename T>
ostream& operator << (ostream& os, vector<T>tmp){
    os << "[";
    for(auto x : tmp) os << " " << x;
    os << " ]";
 
    return os;
}

template <typename T>
ostream& operator << (ostream& os, set<T>tmp){
    os << "[";
    for(auto x : tmp) os << " " << x;
    os << " ]";
 
    return os;
}
 
template <typename T>
ostream& operator << (ostream& os, multiset<T>tmp){
    os << "[";
    for(auto x : tmp) os << " " << x;
    os << " ]";
 
    return os;
}

const ll MOD = 998244353;
const ll N = 4e5;
const ll INF = 2e18;

// modulo operations
void add(ll &a, ll b) { a = (a + b) % MOD; }
void sub(ll &a, ll b) { a -= b; while(a < 0) a += MOD; a %= MOD; }
void mul(ll &a, ll b) { a = (a * b) % MOD; }

ll expo(ll a, ll b) {
    ll ans = 1;
    while(b > 0){
        if(b & 1) mul(ans, a);
        mul(a, a);
        b /= 2;
    }

    return ans;
}

int32_t main(){
    ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
    int tc = 1;
    // cin >> tc;
    for(;tc--;){
        ll n; cin >> n;
        vector<pii> items(n + 5);
        for(int i = 1; i <= n; i++){
            cin >> items[i].fi >> items[i].sec;
        }
        sort(items.begin() + 1, items.begin() + 1 + n);
        
        vector<ll> ps(n + 5);
        for(int i = 1; i <= n; i++) ps[i] = ps[i - 1] + items[i].sec;
        
        ll mx = 0, ans = 0;
        for(int i = 1; i <= n; i++){
            mx = max(mx, -ps[i - 1] + items[i].fi);
            ans = max(ans, ps[i] - items[i].fi + mx);
        }

        cout << ans << "\n";
    }   
}

/*

*/

• Subtask 1: 10 / 10
• Subtask 2: 20 / 20
• Subtask 3: 20 / 20
• Subtask 4: 50 / 50