// dp[i][j] = the number of ways if consider the first i people and j people get colored paintings
/*
* transition
* dp[i][j] = ((dp[i-1][j-1] * a[i]) +(dp[i-1][j]* b[i])) % MOD;
*/
#include <iostream>
#include <vector>
#include <algorithm>
#include <queue>
#include <set>
#include <map>
#define INF 1e9
typedef long long ll;
using namespace std;
const ll MOD = 10007;
ll dp[100005][25];
void solve()
{
int n, c; cin >> n >> c;
vector<ll>a(n + 1), b(n + 1);
for (int i = 1; i <= n; i++)cin >> a[i];
for (int i = 1; i <= n; i++)cin >> b[i];
int q; cin >> q;
while (q--) {
ll p, A, B; cin >> p >> A >> B;
a[p] = A; b[p] = B;
dp[1][0] = b[1];
dp[1][1] = a[1];
for (int i = 2; i <= n; i++) {
for (int j = 0; j <= i; j++) {
if (j == 0) dp[i][j] = (dp[i - 1][j] * b[i]) % MOD;
else {
dp[i][j] = ((dp[i - 1][j - 1] * a[i]) + (dp[i - 1][j] * b[i])) % MOD;
}
}
}
cout << dp[n][c] << "\n";
}
}
int main()
{
ios_base::sync_with_stdio(0);
cin.tie(0);
int t = 1;// cin >> t;
while (t--) solve();
return 0;
}
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