Submission #11365

#	Time	Username	Problem	Language	Result	Execution time	Memory
11365		gs14004	Board (CEOI13_board)	C++98	10 / 100	4 ms	2084 KiB

board

#include <cstdio>
#include <vector>
#include <cstdlib>
#include <algorithm>
using namespace std;

struct big{
    vector<int> s;
    void i(){
        s.push_back(1);
    }
    void one(){
        s.push_back(0);
    }
    void two(){
        s.push_back(1);
    }
    void l(){
        s.back()--;
    }
    void r(){
        s.back()++;
    }
    void u(){
        int r = s.back();
        s.pop_back();
        if(r >= 0){
            s.back() += r/2;
            r %= 2;
        }
        else{
            s.back() -= r/2 * 2;
            r -= r/2 * 2;
            while(r < 0) s.back()--, r += 2;
        }
    }
    int ret(){
        if(s.empty()) return -1;
        int r = s.back();
        s.pop_back();
        if(r >= 0){
            s.back() += r/2;
            r %= 2;
        }
        else{
            s.back() -= r/2 * 2;
            r -= r/2 * 2;
            while(r < 0) s.back()--, r += 2;
        }
        return r;
    }
}x,y;

int main(){
    char str1[100005], str2[100005];
    scanf("%s %s",str1,str2);
    x.i();
    y.i();
    for (int i=0; str1[i]; i++) {
        if(str1[i] == '1') x.one();
        if(str1[i] == '2') x.two();
        if(str1[i] == 'L') x.l();
        if(str1[i] == 'R') x.r();
        if(str1[i] == 'U') x.u();
    }
    for (int i=0; str2[i]; i++) {
        if(str2[i] == '1') y.one();
        if(str2[i] == '2') y.two();
        if(str2[i] == 'L') y.l();
        if(str2[i] == 'R') y.r();
        if(str2[i] == 'U') y.u();
    }
    vector<char> r1,r2;
    while (1) {
        int r = x.ret();
        if(r == -1) break;
        r1.push_back(r);
    }
    while (1) {
        int r = y.ret();
        if(r == -1) break;
        r2.push_back(r);
    }
    reverse(r1.begin(),r1.end());
    reverse(r2.begin(),r2.end());
    int res = (int)(r1.size() + r2.size());
    int piv = 0;
    while (piv < r1.size() && piv < r2.size() && r1[piv] == r2[piv]) {
        res-=2;
        piv++;
    }
    int rr = res;
    int dist = 0;
    while (piv < r1.size() && piv < r2.size()) {
        dist <<= 1;
        dist += r2[piv] - r1[piv];
        res -= 2;
        piv++;
        rr = min(rr,res + abs(dist));
        if(abs(dist) > 1000000) break;
    }
    printf("%d",rr);
}

• Subtask 1: 0 / 10
• Subtask 2: 0 / 10
• Subtask 3: 0 / 10
• Subtask 4: 0 / 10
• Subtask 5: 10 / 10
• Subtask 6: 0 / 10
• Subtask 7: 0 / 10
• Subtask 8: 0 / 10
• Subtask 9: 0 / 10
• Subtask 10: 0 / 10