// #include "wiring.h"
#include <cassert>
#include <cstdio>
#include <vector>
#include <climits>
#include <stdlib.h>
#include <algorithm>
#include <iostream>
using namespace std;
bool isSubtask1(const vector<int>& r, const vector<int>& b) {return r.size()<=200 && b.size()<=200;}
bool isSubtask2(const vector<int>& r, const vector<int>& b) {return r[r.size()-1]<b[0];}
bool isSubtask3(const vector<int>& r, const vector<int>& b) {
int n=r.size(), m=b.size();
vector<int> a(n+m);
for(int i=0, j=0; i<n || j<m;)
i==n? a[i+j++]=1: j==m? a[j+i++]=0: r[i]<b[j]? a[j+i++]=0:a[i+j++] = 1;
int cnt = 1;
for(int k=1; k<n+m; k++) {
cnt = a[k]==a[k-1]? cnt+1:0;
if (cnt > 6) return false;
}
return true;
}
bool isSubtask4(const vector<int>& r, const vector<int>& b) {
return min(r[0],b[0])==1 && max(r[r.size()-1],b[b.size()-1])==r.size()+b.size();
}
long long subtask1(const vector<int>&, const vector<int>&);
long long subtask2(const vector<int>&, const vector<int>&);
pair<int,int> initSubtask2(const vector<int>&, const vector<int>&, vector<long long>&);
long long subtask3(const vector<int>&, const vector<int>&);
long long subtask4(const vector<int>&, const vector<int>&);
long long fulltask(const vector<int>&, const vector<int>&);
long long min_total_length(vector<int>, vector<int> );
long long min_total_length(vector<int> r, vector<int> b) {
return fulltask(r,b);
if (isSubtask4(r,b)) return subtask4(r,b);
else if (isSubtask3(r,b)) return subtask3(r,b);
else if (isSubtask2(r,b)) return subtask2(r,b);
else if (isSubtask1(r,b)) return subtask1(r,b);
return 0;
}
long long fulltask(const vector<int>& r, const vector<int>& b) {
int n = r.size(), m = b.size();
vector<int> val(n+m), color(n+m);
for(int i=0, j=0; i<n || j<m;) // ++ is not permitted in make_pair
if (j==m || i<n && r[i]<b[j]) val[j+i++]=r[i];
else {color[i+j]=1; val[i+j++]=b[j];}
vector<long long> dp(n+m,LLONG_MAX);
int endL=0, endR=n+m-1;
tie(endL,endR) = initSubtask2(val,color,dp);
long long sumL=0, cntL=0, sumR=0, cntR=0, gap=0;
int startL=0, startR=endL+1, optIdx=0;
for(int i=endR+1; i<n+m; i++) {
if (color[i] != color[i-1]) {
startL=startR; startR=i; sumR=cntR=0; sumL=0; optIdx=startR-1;
gap = val[startR]-val[startR-1];
}
sumR += val[i]-val[startR]; cntR++;
for(int j=optIdx; j>=startL; j--) {
cntL=startR-j;
sumL += val[startR-1]-val[j];
long long temp = sumL + sumR + max(cntL,cntR)*gap;
temp += min(dp[j-1],dp[j]);
if (dp[i]>temp) {dp[i]=temp; optIdx=j;}
else break;
}
for(int k=max(optIdx-1,startL); k<=optIdx; k++)
sumL -= val[startR-1]-val[k];
}
return dp[n+m-1];
}
long long subtask4(const vector<int>& r, const vector<int>& b) {
int n = r.size(), m = b.size();
vector<int> color(n+m);
for(int i=0, j=0; i<n || j<m;)
i==n? color[i+j++]=1: j==m? color[j+i++]=0: r[i]<b[j]? color[j+i++]=0: color[i+j++]=1;
long long dp1=LLONG_MAX, dp2=LLONG_MAX;
long long cntL=0, cntR=1;
int startL=-1, startR=0;
for(int i=1; i<n+m; i++) {
// new block starts
if (color[i]!=color[i-1]) {startL=startR; startR=i; cntL=cntR, cntR=0;}
cntR++;
// not the end of a block
if(i<n+m-1 && color[i]==color[i+1]) continue;
long long cntL1 = cntL/2, cntL2 = (cntL+1)/2;
long long cntR1 = cntR/2, cntR2 = (cntR+1)/2;
long long sumL = cntL*(cntL-1)/2, sumR = cntR*(cntR-1)/2;
long long sumL1 = cntL1*(cntL1-1)/2, sumL2 = cntL2*(cntL2-1)/2;
long long sumR1 = cntR1*(cntR1-1)/2, sumR2 = cntR2*(cntR2-1)/2;
if(i==n+m-1) { //the last block
if(startL==0) // can be omitted because it is the same as subtask2
return sumL + max(cntL,cntR) + sumR;
else
return min(dp1 + sumL2 + max(cntL2,cntR), dp2 + sumL1 + max(cntL1,cntR)) + sumR;
}
else if (color[i]!= color[i+1]) { // not the last block
if (startL==0) {
dp1 = sumL + max(cntL,cntR1) + sumR1;
dp2 = sumL + max(cntL,cntR2) + sumR2;
}
else {
long long new_dp1 = min(dp1 + sumL2 + max(cntL2,cntR1), dp2 + sumL1 + max(cntL1,cntR1)) + sumR1;
long long new_dp2 = min(dp1 + sumL2 + max(cntL2,cntR2), dp2 + sumL1 + max(cntL1,cntR2)) + sumR2;
dp1 = new_dp1; dp2 = new_dp2;
}
}
}
}
long long subtask3(const vector<int>& r, const vector<int>& b) {
int n = r.size(), m = b.size();
vector<int> val(n+m), color(n+m);
for(int i=0, j=0; i<n || j<m;)
if (j==m || i<n && r[i]<b[j]) val[j+i++]=r[i];
else {color[i+j]=1; val[i+j++]=b[j];}
vector<long long> dp(n+m,LLONG_MAX);
int endL=0, endR=n+m-1;
tie(endL,endR) = initSubtask2(val,color,dp);
long long sumL=0, cntL=0, sumR=0, cntR=0, gap=0;
int startL=0, startR=endL+1;
for(int i=endR+1; i<n+m; i++) {
if(color[i]!=color[i-1]) {
startL=startR; startR=i; sumR=cntR=0;
gap=val[startR]-val[startR-1];
}
sumR += val[i]-val[startR]; cntR++;
for(int j=startR-1; j>=startL; j--) {
sumL += val[startR-1]-val[j]; cntL++;
long long temp = sumL + sumR + max(cntL,cntR)*gap;
temp += min(dp[j-1],dp[j]);
dp[i] = min(dp[i], temp);
}
sumL=cntL=0;
}
return dp[n+m-1];
}
pair<int,int> initSubtask2(const vector<int>& val, const vector<int>& color, vector<long long>& dp) {
long long sum1=0, sum2=0;
long long n = val.size();
long long endL=n-1, endR=n-1;
for(int i=1; i<n; i++) if (color[i] != color[i-1]) {endL = i-1; break;}
for(int i=endL+2; i<n; i++) if (color[i] != color[i-1]) {endR = i-1; break;}
for(int i=0; i<endL; i++) sum1 += val[endL] - val[i];
for(int i=endL+1; i<=endR; i++) {
sum2 += val[i] - val[endL+1];
dp[i] = sum1+sum2+max(endL+1,i-endL)*(val[endL+1]-val[endL]);
}
return {endL,endR};
}
long long subtask2(const vector<int>& r, const vector<int>& b) {
long long sum1=0, sum2=0, n=r.size(), m=b.size();
for(int i=0; i<n; i++) sum1 += r[n-1] - r[i];
for(int i=0; i<m; i++) sum2 += b[i] - b[0];
return sum1+sum2+max(n,m)*(b[0]-r[n-1]);
}
long long subtask1(const vector<int>& r, const vector<int>& b) {
int n = r.size(), m = b.size();
long long dp[n][m];
dp[0][0] = abs(r[0]-b[0]);
for(int i=1; i<n; i++) dp[i][0] = dp[i-1][0] + abs(r[i]-b[0]);
for(int j=1; j<m; j++) dp[0][j] = dp[0][j-1] + abs(r[0]-b[j]);
for(int i=1; i<n; i++)
for(int j=1; j<m; j++)
dp[i][j] = min(min(dp[i-1][j],dp[i][j-1]),dp[i-1][j-1]) + abs(r[i]-b[j]);
return dp[n-1][m-1];
}
