제출 #1135996

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1135996		nightfal	전선 연결 (IOI17_wiring)	C++20	55 / 100	20 ms	4924 KiB

wiring

// #include "wiring.h"
#include <cassert>
#include <cstdio>
#include <vector>
#include <climits>
#include <stdlib.h>
#include <algorithm>

using namespace std;
 
bool isSubtask1(const vector<int>& r, const vector<int>& b) {return r.size()<=200 && b.size()<=200;}
bool isSubtask2(const vector<int>& r, const vector<int>& b) {return r[r.size()-1]<b[0];}
bool isSubtask3(const vector<int>& r, const vector<int>& b) {
    int n=r.size(), m=b.size();
    vector<int> a(n+m);
   
    for(int i=0, j=0; i<n || j<m;)
        i==n? a[i+j++]=1: j==m? a[j+i++]=0: r[i]<b[j]? a[j+i++]=0:a[i+j++] = 1;

    int cnt = 1;
    for(int k=1; k<n+m; k++) {
        cnt = a[k]==a[k-1]? cnt+1:0;
        if (cnt > 6) return false;
    }
  return true;
}
bool isSubtask4(const vector<int>& r, const vector<int>& b) {
    return min(r[0],b[0])==1 && max(r[r.size()-1],b[b.size()-1])==r.size()+b.size();
}
 
long long subtask1(const vector<int>&, const vector<int>&);
long long subtask2(const vector<int>&, const vector<int>&);
pair<int,int> initSubtask2(const vector<int>&, const vector<int>&, vector<long long>&);
long long subtask3(const vector<int>&, const vector<int>&);
long long subtask4(const vector<int>&, const vector<int>&);
long long fulltask(vector<int>, vector<int>);
long long min_total_length(vector<int>, vector<int> );


 
long long min_total_length(vector<int> r, vector<int> b) {
//    return fulltask(r,b);
    if (isSubtask4(r,b)) return subtask4(r,b);
    else if (isSubtask3(r,b)) return subtask3(r,b);
  	else if (isSubtask2(r,b)) return subtask2(r,b);    
  	 else if (isSubtask1(r,b)) return subtask1(r,b);
    return 0;
}

long long fulltask(vector<int> r, vector<int> b) {
    int n = r.size(), m = b.size();
    vector<pair<int,int>> a(n+m);
    // vector<int> val(n+m), color(n+m);
    
    for(int i=0, j=0; i<n || j<m;) // ++ is not permitted in make_pair 
        i==n? a[i+j++]=make_pair(j,1): j==m? a[j+i++]=make_pair(i,0): r[i]<b[j]? a[j+i++]=make_pair(i,0): a[i+j++]=make_pair(j,1);
        // if (i==n || j<m && r[i]>b[j]) {color[i+j]=1; val[i+j]=b[j++]; }
        // else {val[i+j]=r[i++];}
    vector<long long> dp(n+m,LLONG_MAX);

    long long sumL=0, cntL=0, sumR=0, cntR=0, gap=0;
    int prev=-1, curr=0, optIdx=0;

    for(int i=1; i<n+m; i++) {
        vector<int> *left, *right;
        if (a[i].second != a[i-1].second) {
            prev=curr; curr=i; sumR=cntR=0; sumL=0; optIdx=curr-1;
            if (a[prev].second==0) {left=&r; right=&b;}
            else {left=&b; right=&r;}
            gap = (*right)[a[curr].first]-(*left)[a[curr-1].first];
        }

        if (prev==-1) continue;

        sumR += (*right)[a[i].first]-(*right)[a[curr].first];
        cntR++;

        for(int j=optIdx; j>=prev; j--) {
            cntL=curr-j; 
            sumL += (*left)[a[curr-1].first]-(*left)[a[j].first];
            if(prev==0 && j!=0) continue;
            long long temp = sumL + sumR + max(cntL,cntR)*gap;
            if (prev!=0) temp += min(dp[j-1],dp[j]);
            if (dp[i]>temp) {dp[i]=temp; optIdx=j;}
                else break;            
        }
        for(int k=max(optIdx-1,prev); k<=optIdx; k++)
            sumL -= (*left)[a[curr-1].first]-(*left)[a[k].first];
    }
    return dp[n+m-1];
}

long long subtask4(const vector<int>& r, const vector<int>& b) {
    int n = r.size(), m = b.size();
    vector<int> color(n+m);
    
    for(int i=0, j=0; i<n || j<m;)
        i==n? color[i+j++]=1: j==m? color[j+i++]=0: r[i]<b[j]? color[j+i++]=0: color[i+j++]=1;

    long long dp1=LLONG_MAX, dp2=LLONG_MAX;
    long long cntL=0, cntR=1;
    int startL=-1, startR=0; 

    for(int i=1; i<n+m; i++) {
        if (color[i]!=color[i-1]) {startL=startR; startR=i; cntL=cntR, cntR=0;}
        cntR++;

        if(i<n+m-1 && color[i]==color[i+1]) continue;

        long long cntL1 = cntL/2, cntL2 = (cntL+1)/2;                
        long long cntR1 = cntR/2, cntR2 = (cntR+1)/2;

        long long sumL = cntL*(cntL-1)/2, sumR = cntR*(cntR-1)/2; 
        long long sumL1 = cntL1*(cntL1-1)/2, sumL2 = cntL2*(cntL2-1)/2; 
        long long sumR1 = cntR1*(cntR1-1)/2, sumR2 = cntR2*(cntR2-1)/2;

        if(i==n+m-1) {
            if(startL==0) // can be omitted because it is the same as subtask2
                return sumL + max(cntL,cntR) + sumR;
            else 
                return min(dp1 + sumL2 + max(cntL2,cntR), dp2 + sumL1 + max(cntL1,cntR)) + sumR;
        }
        else if (color[i]!= color[i+1]) { 
            if (startL==0) {
                dp1 = sumL + max(cntL,cntR1) + sumR1; 
                dp2 = sumL + max(cntL,cntR2) + sumR2;            
            }
            else {
                long long new_dp1 = min(dp1 + sumL2 + max(cntL2,cntR1), dp2 + sumL1 + max(cntL1,cntR1)) + sumR1;
                long long new_dp2 = min(dp1 + sumL2 + max(cntL2,cntR2), dp2 + sumL1 + max(cntL1,cntR2)) + sumR2;
                dp1 = new_dp1; dp2 = new_dp2;
            }
        }
    }
}

long long subtask3(const vector<int>& r, const vector<int>& b) {
    int n = r.size(), m = b.size();
    vector<int> val(n+m), color(n+m);

    for(int i=0, j=0; i<n || j<m;) 
        if (j==m || i<n && r[i]<b[j]) val[j+i++]=r[i];
        else {color[i+j]=1; val[i+j++]=b[j];}

    vector<long long> dp(n+m,LLONG_MAX);
    int endL=0, endR=n+m-1;
    tie(endL,endR) = initSubtask2(val,color,dp);

    long long sumL=0, cntL=0, sumR=0, cntR=0, gap=0;
    int startL=0, startR=endL+1;

    for(int i=endR+1; i<n+m; i++) {
        if(color[i]!=color[i-1]) {
            startL=startR; startR=i; sumR=cntR=0; 
            gap=val[startR]-val[startR-1];
        }
        sumR += val[i]-val[startR]; cntR++;
        for(int j=startR-1; j>=startL; j--) {
            sumL += val[startR-1]-val[j]; cntL++;
            long long temp = sumL + sumR + max(cntL,cntR)*gap;
            temp += min(dp[j-1],dp[j]);
            dp[i] = min(dp[i], temp);
        }
        sumL=cntL=0;
    }
    return dp[n+m-1];
}
pair<int,int> initSubtask2(const vector<int>& val, const vector<int>& color, vector<long long>& dp) {
    long long sum1=0, sum2=0;
    int n = val.size(); int endL=n-1, endR=n-1;
    for(int i=1; i<n; i++) if (color[i] != color[i-1]) {endL = i-1; break;}
    for(int i=endL+2; i<n; i++)  if (color[i] != color[i-1]) {endR = i-1; break;}    
    for(int i=0; i<endL; i++) sum1 += val[endL] - val[i];
    for(int i=endL+1; i<=endR; i++) { 
        sum2 += val[i] - val[endL+1];
        dp[i] = sum1+sum2+max(endL+1,i-endL)*(val[endL+1]-val[endL]);
    }
    return {endL,endR};
}
long long subtask2(const vector<int>& r, const vector<int>& b) {
  long long sum1=0, sum2=0, n=r.size(), m=b.size();
  for(int i=0; i<n; i++) sum1 += r[n-1] - r[i];
  for(int i=0; i<m; i++) sum2 += b[i] - b[0];
  return sum1+sum2+max(n,m)*(b[0]-r[n-1]);
}
long long subtask1(const vector<int>& r, const vector<int>& b) {
	int n = r.size(), m = b.size();
    long long dp[n][m];
  	dp[0][0] = abs(r[0]-b[0]);
  	for(int i=1; i<n; i++) dp[i][0] = dp[i-1][0] + abs(r[i]-b[0]);
    for(int j=1; j<m; j++) dp[0][j] = dp[0][j-1] + abs(r[0]-b[j]);
  	for(int i=1; i<n; i++)  	
      for(int j=1; j<m; j++)
        dp[i][j] = min(min(dp[i-1][j],dp[i][j-1]),dp[i-1][j-1]) + abs(r[i]-b[j]);

	return dp[n-1][m-1];
}

컴파일 시 표준 에러 (stderr) 메시지

wiring.cpp: In function 'long long int subtask4(const std::vector<int>&, const std::vector<int>&)':
wiring.cpp:135:1: warning: control reaches end of non-void function [-Wreturn-type]
  135 | }
      | ^

• Subtask 1: 7 / 7
• Subtask 2: 13 / 13
• Subtask 3: 10 / 10
• Subtask 4: 25 / 25
• Subtask 5: 0 / 45