#include <bits/stdc++.h>
#define int long long
#define ll long long
#define pb push_back
#define fi first
#define se second
#define lf (id<<1)
#define rg ((id<<1)|1)
#define md ((l+r)>>1)
#define ld long double
using namespace std;
typedef pair<int,int> pii;
typedef pair<char,char> pcc;
typedef pair<int,pii> ipii;
typedef pair<pii,pii> ipiii;
const int MAXN = 5e5+10;
const int SQRT = 610;
const int MAXA = 50;
const int MOD = 1e6+7;
const int INF = 1e18+10;
const int LOG = 30;
const ld EPS = 1e-12;
int sum(int a, int b){ return (a+b)%MOD; }
int mul(int a, int b){ return (1ll*a*b)%MOD; }
void chsum(int &a, int b){ a = (a+b)%MOD; }
void chmul(int &a, int b){ a = (1ll*a*b)%MOD; }
int n,q,a[MAXN], ans[MAXN];
vector <pii> vec[MAXN];
struct seg {
int st[4*MAXN],laz[4*MAXN];
void bnc(int id, int l, int r){
if(laz[id]==0) return;
st[lf]+=laz[id]; laz[lf]+=laz[id];
st[rg]+=laz[id]; laz[rg]+=laz[id];
laz[id] = 0;
}
int que(int id, int l, int r, int x, int y){
if(x<=l && r<=y) return st[id];
if(r<x || y<l) return INF;
bnc(id,l,r);
return min(que(lf,l,md,x,y), que(rg,md+1,r,x,y));
}
int upd(int id, int l, int r, int x, int y, int p){
if(x<=l && r<=y){laz[id]+=p; return st[id] += p; }
if(r<x || y<l) return st[id];
bnc(id,l,r);
return st[id] = min(upd(lf,l,md,x,y,p), upd(rg,md+1,r,x,y,p));
}
} A, B;
signed main(){
ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
cin>>n;
string s; cin>>s;s='.'+s;
for(int i=1; i<=n; i++) a[i] = (s[i]=='C' ? 1 : -1);
cin>>q;
for(int i=1; i<=q; i++){
int l,r;cin>>l>>r;
vec[l].pb({r, i});
}
set <int> t; int lef = 0;
for(int l=n; l>=1; l--){
if(s[l]=='C'){
if(!t.empty()){
int nx = *t.begin(); t.erase(nx);
A.upd(1,1,n+1,1,nx,-1); // reactivate
B.upd(1,1,n+1,nx,n+1,1);
}
A.upd(1,1,n+1,1,l,1); // dari n
} else {
t.insert(l); B.upd(1,1,n+1,l,n+1,-1);
}
for(auto [r, id] : vec[l]){
ans[id] = -B.que(1,1,n+1,l,r)
-min(0ll,A.que(1,1,n+1,l,r)-A.que(1,1,n+1,r+1,r+1));
// cout << l <<' '<<r<<' '<< lef<<"lef\n";
// for(int i=1; i<=n; i++) cout << A.que(1,1,n+1,i,i) << " \n"[i==n];
}
}
for(int i=1; i<=q; i++) cout << ans[i] << '\n';
}
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