제출 #1133792

#제출 시각아이디문제언어결과실행 시간메모리
1133792t9unkubj말 (IOI15_horses)C++20
컴파일 에러
0 ms0 KiB

#ifdef t9unkubj
#include"debug.cpp"
//#include"template_no_debug.h"
#else 
#include "horses.h"
#define dbg(...) 199958
#endif

#pragma GCC optimize("O3")
using namespace std;
#include<bits/stdc++.h>
using ll=long long;
using ull=unsigned long long;
template<class T>using vc=vector<T>;
template<class T>using vvc=vc<vc<T>>;
#define rep(i,n) for(ll i=0;i<(ll)(n);i++)
#define REP(i,j,n) for(ll i=(j);i<(ll)(n);i++)
#define DREP(i,n,m) for(ll i=(n);i>=(m);i--)
#define drep(i,n) for(ll i=((n)-1);i>=0;i--)
#define all(x) x.begin(),x.end()
#define rall(x) x.rbegin(),x.rend()
template<class T,class F>
bool chmin(T &x, F y){
    if(x>y){
        x=y;
        return true;
    }
    return false;
}
template<class T, class F>
bool chmax(T &x, F y){
    if(x<y){
        x=y;
        return true;
    }
    return false;
}
double pass_time=0;
template<class T,class G,class F>
F modpow(T x,G p,F m){
    T ret=1%m;
    x%=m;
    while(p){
        if(p&1)ret=(1ll*ret*x)%m;
        x=(1ll*x*x)%m;
        p>>=1;
    }
    return ret;
}
template<class T>
T extgcd(T a,T b,T&x,T&y){//ax+by=gcd(a,b)となるようなもの
    if(b==0){
        x=1;
        y=0;
        return a;
    }else{
        T res=extgcd(b,a%b,y,x);
        y-=(a/b)*x;
        return res;
    }
}
template<class T>
pair<T,T> inv(T x,T m){
    T a1,a2;
    T res=extgcd(x,m,a1,a2);
    return {a1,m/res};
}
constexpr int mod=1e9+7;
struct mint{
    long long val;
    inline long long fast(long long x){
        if(x<mod&&x>=0)return x;
        x%=mod;
        if(x<0)x+=mod;
        return x;
    }
    mint():val(0){}
    mint(long long val):val(fast(val)){}
    mint power(long long m)const {
        mint res(1);
        mint ret(*this);
        while(m){
           if(m&1)res*=ret;
           ret*=ret;
           m>>=1;
        }
        return res;
    }
    mint& operator++() {
        val++;
        if (val == mod) val = 0;
        return *this;
    }
    mint& operator--() {
        if (val == 0)val=mod;
        val--;
        return *this;
    }
    mint operator++(int) {
        mint result = *this;
        ++*this;
        return result;
    }
    mint operator--(int) {
        mint result = *this;
        --*this;
        return result;
    }
    mint operator-() const { 
      return mint(-val);
    }
    friend mint operator +(const mint&a,const mint&b) noexcept{
        return mint(a)+=b;
    }
    friend mint operator -(const mint&a,const mint&b) noexcept{
        return mint(a)-=b;
    }
    friend mint operator *(const mint&a,const mint&b) noexcept{
        return mint(a)*=b;
    }
    friend mint operator /(const mint&a,const mint&b) noexcept{
        return mint(a)/=b;
    }
    mint& operator+=(const mint&a)noexcept{
        val+=a.val;
        if(val>=mod)val-=mod;
        return *this;
    }
    mint& operator-=(const mint&a)noexcept{
        val-=a.val;
        if(val<0)val+=mod;
        return *this;
    }
    mint& operator*=(const mint&a){
        val*=a.val;
        val=fast(val);
        return *this;
    }
    mint& operator/=(const mint&a){
        val*=inv<long long>(a.val,mod).first;
        val=fast(val);
        return *this;
    }
    bool operator == (const mint&x)const noexcept{
        return this->val==x.val;
    }
    bool operator != (const mint&x)const noexcept{
        return this->val!=x.val;
    }
    friend ostream& operator << (ostream &os, const mint &x) noexcept {
        return os << x.val;
    }
    friend istream& operator >> (istream &is,  mint &x) noexcept {
        long long v;
        is >> v;
        x=mint(v);
        return is;
    }
};
vector<mint>fact(1,1),invfact(1,1);
void build(int n){
    if(n<(int)fact.size())return;
    fact=invfact=vector<mint>(n+1);
    fact[0]=1;
    for(int i=1;i<=n;i++)fact[i]=fact[i-1]*i;
    invfact[n]=(1/fact[n]);
    for(int i=n-1;i>=0;i--)invfact[i]=invfact[i+1]*(i+1);
}
mint C(int a,int b){//aCb
    if(a<0||b<0||a-b<0)return mint(0);
    while((int)fact.size()<=a){
        fact.push_back(fact.back()*(fact.size()));
    }
    while((int)invfact.size()<=a){
        invfact.push_back(invfact.back()/invfact.size());
    }
    return fact[a]*invfact[b]*invfact[a-b];
}
mint P(int a,int b){
    if(a<b||b<0)return 0;
    return fact[a]*invfact[a-b];
}
//a個のものからb個を重複を許して選ぶ
mint H(int a,int b){
    return C(a+b-1,b);
}
void print(mint a) { cout << a; }
template<class T>
pair<T,T> mod_solve(T a,T b,T m){//ax=b mod mとなるxを返す
    a%=m,b%=m;if(a<0)a+=m;if(b<0)b+=m;
    T g=gcd(gcd(a,b),m);
    a/=g,b/=g,m/=g;
    if(gcd(a,m)>1)return {-1,-1};
    return {(inv(a,m).first*b)%m,inv(a,m).second};
}
template<class T,auto op>
struct segtree{
    int n;
    vc<T>node;
    T e;
    segtree(int n,T e):n(n),e(e),node(n*2,e){}
    void set(int i,T x){
        node[i+=n]=x;
        while(i>>=1)node[i]=op(node[i*2],node[i*2+1]);
    }
    T prod(int l,int r){
        l+=n,r+=n;
        T sml=e,smr=e;
        while(l<r){
            if(l&1)sml=op(sml,node[l++]);
            if(r&1)smr=op(node[--r],smr);
            l/=2,r/=2;
        }
        return op(sml,smr);
    }
};

ll op(ll a,ll b){
    return a*b;
}
mint op2(mint a,mint b){
    return a*b;
}
ll op3(ll a,ll b){
    return max(a,b);
}
using i128=__int128;
constexpr int N_=5e5;
int x[N_],y[N_];
set<int>non_zero;
segtree<ll,op>seg(N_,1);
segtree<mint,op2>seg2(N_,1);
segtree<ll,op3>ymax(N_,0);
int n;
mint answer(){
   {
        vc<int>is;
        ll now=1;
        for(auto itr=non_zero.rbegin();itr!=non_zero.rend();itr++){
            is.push_back(*itr);
            now*=x[*itr];
            if(now>1e9)break;
        }
        if(now<=1e9&&x[0]==1){
            is.push_back(0);
        }
        dbg(is);
        reverse(all(is));
        is.push_back(n);
        array<i128,3>ans{};
        REP(i,1,is.size()){
            int l=is[i-1],r=is[i];
            //[l,r)
            if(ans[0]<i128(seg.prod(is[0],r))*ymax.prod(l,r)){
                ans={i128(seg.prod(is[0],r))*ymax.prod(l,r),l,r};
            }
        }
        return ymax.prod(ans[1],ans[2])*seg2.prod(0,ans[2]);
    }
}
int init(int N, int X[], int Y[]){
    n=N;
    rep(i,N)x[i]=X[i];
    rep(i,N)y[i]=Y[i];

    rep(i,N)seg.set(i,x[i]);
    rep(i,N)seg2.set(i,x[i]);
    rep(i,N)ymax.set(i,y[i]);
    rep(i,N){
        if(x[i]>1){
            non_zero.insert(i);
        }
    }
    return answer().val;
}

int updateX(int pos, int val) {
    if(x[pos]!=1){
        non_zero.erase(pos);
    }
    x[pos]=val;
    if(x[pos]!=1){
        non_zero.insert(pos);
    }
    seg.set(pos,val);
    seg2.set(pos,val);
	return answer().val;
}

int updateY(int pos, int val) {
    ymax.set(pos,val);
	return answer().val;
}
namespace judge{
    void run(){
        int n;
        cin>>n;
        int x[n],y[n];
        rep(i,n)cin>>x[i];
        rep(i,n)cin>>y[i];
        dbg(init(n,x,y));
        int m;
        cin>>m;
        while(m--){
            int t,p,v;
            cin>>t>>p>>v;
            if(t==1)dbg(updateX(p,v));
            else dbg(updateY(p,v));
        }
    }
};
int main(){judge::run();}
/*
10 
100 20 34 40 50 60 60 60 90 100
1 2 3 4 5 6 7 8 8 10
5
1 1 2
1 4 6
1 3 4
1 2 5
1 2 21901010
*/

컴파일 시 표준 에러 (stderr) 메시지

/usr/bin/ld: /tmp/ccyZGy6L.o: in function `main':
grader.c:(.text.startup+0x0): multiple definition of `main'; /tmp/cc3jEMx6.o:horses.cpp:(.text.startup+0x0): first defined here
collect2: error: ld returned 1 exit status