제출 #1130278

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1130278		gyg	Sličnost (COI23_slicnost)	C++20	50 / 100	592 ms	350632 KiB

Main

#include <bits/stdc++.h>
using namespace std;
#define int long long 
#define arr array 
#define pii pair<int, int>
#define fir first 
#define sec second
const int N = 1e5 + 5;

int n, k, q;
arr<int, N> a, b;

struct Sg {
    struct Nd {
        int mx, nm, lzy;
        Nd *lf, *rg;
        Nd(int x, int y, int z = 0, Nd *l = nullptr, Nd *r = nullptr) {
            mx = x, nm = y, lzy = z, lf = l, rg = r;
        }
        Nd(Nd *l, Nd *r) {
            mx = max(l->mx, r->mx);
            nm = ((l->mx == mx) ? l->nm : 0) + ((r->mx == mx) ? r->nm : 0);
            lzy = 0, lf = l, rg = r;
        }
    };
    arr<Nd*, N> rt;
    void prp(Nd *u, int lw, int hg) {
        int md = (lw + hg) / 2;
        if (!u->lf) 
            u->lf = new Nd(0, md - lw + 1), u->rg = new Nd(0, hg - md);
        for (Nd *v : {u->lf, u->rg}) 
            v->mx += u->lzy, v->lzy += u->lzy;
        u->lzy = 0;
    }
    Nd* upd(int l, int r, int x, Nd *u, int lw = 1, int hg = n - k + 1) {
        l = max(l, 1ll), r = min(r, n - k + 1);
        assert(l <= r);
        if (r < lw || hg < l) return u;
        if (l <= lw && hg <= r) return new Nd(u->mx + x, u->nm, u->lzy + x, u->lf, u->rg);
        prp(u, lw, hg);
        int md = (lw + hg) / 2;
        return new Nd(upd(l, r, x, u->lf, lw, md), upd(l, r, x, u->rg, md + 1, hg));
    }
} sg;

arr<int, N> ps;
map<int, int> cnt;
void prnt() { cout << cnt.rbegin()->fir << " " << cnt.rbegin()->sec << endl; }
void prcmp() {
    for (int i = 1; i <= n; i++)
        ps[b[i]] = i;
    
    sg.rt[1] = new Sg::Nd(0, n - k + 1);
    for (int i = 1; i <= k; i++) {
        int id = ps[a[i]];
        sg.rt[1] = sg.upd(id - k + 1, id, +1, sg.rt[1]);
    }
    for (int i = 2; i <= n - k + 1; i++) {
        int lf_id = ps[a[i - 1]], rg_id = ps[a[i + k - 1]];
        sg.rt[i] = sg.upd(lf_id - k + 1, lf_id, -1, sg.rt[i - 1]);
        sg.rt[i] = sg.upd(rg_id - k + 1, rg_id, +1, sg.rt[i]);
    }

    for (int i = 1; i <= n - k + 1; i++)
        cnt[sg.rt[i]->mx] += sg.rt[i]->nm;

    // for (int i = 1; i <= n - k + 1; i++) {
    //     cout << i << ": " << sg.rt[i]->mx << " " << sg.rt[i]->nm << endl;
    // }
}
void cmp() {
    prnt();
}

signed main() {
    // freopen("a.in", "r", stdin);
    cin >> n >> k >> q;
    for (int i = 1; i <= n; i++) cin >> a[i];
    for (int i = 1; i <= n; i++) cin >> b[i];
    prcmp(), cmp();
}

• Subtask 1: 7 / 7
• Subtask 2: 10 / 10
• Subtask 3: 33 / 33
• Subtask 4: 0 / 7
• Subtask 5: 0 / 10
• Subtask 6: 0 / 33