Submission #1129338

#	Time	Username	Problem	Language	Result	Execution time	Memory
1129338		zhasyn	Monkey and Apple-trees (IZhO12_apple)	C++20	0 / 100	198 ms	63172 KiB

apple

#include <bits/stdc++.h>
#define pb push_back
#define pf push_front
using namespace std;
#define F first
#define S second
typedef long long ll;
#define pii pair <int, int>
#define pll pair <ll, ll>
typedef long double ld;
const ll N = 2 * 1e6 + 100, M = 500 + 10, len = 315, inf = 1e18;
const ll mod = 998244353;
ll um(ll a, ll b){
	return (1LL * a * b) % mod;
}
ll subr(ll a, ll b){
	return ((1LL * a - b) % mod + mod) % mod;
}
ll bp(ll x, ll step){
	ll res = 1;
	while(step){
		if(step & 1) res = um(res, x);
		x = um(x, x);
		step /= 2;
	}
	return res;
}
ll inv(ll x){
	return bp(x, mod - 2);
}
struct ver{
	bool full;
	ll p[2], ans;
} a[N];

ll ct;
ll create(){
	ll x = ct++;
	a[x].full = false;
	a[x].p[0] = a[x].p[1] = -1;
	a[x].ans = 0;
	return x;
}
ll sz;
struct segtree {
	void init(ll n){
		sz = 1;
		while(sz < n){
			sz *= 2;
		}
	}
	void prop(ll x, ll lx, ll rx){
		if(rx - lx == 1) return;
		if(a[x].p[0] == -1){
			a[x].p[0] = create();
			a[x].p[1] = create();
		}
		if(a[x].full){
			a[a[x].p[0]].full = a[a[x].p[1]].full = 1;
			a[a[x].p[0]].ans = a[a[x].p[1]].ans = (rx - lx) / 2;
		}
	}
	void upd(ll l, ll r, ll x = 0, ll lx = 0, ll rx = sz){
		prop(x, lx, rx);
		if(lx >= r || l >= rx) return;
		if(l <= lx && rx <= r){
			a[x].ans = rx - lx;
			a[x].full = true;
			return;
		}
		ll mid = (lx + rx) / 2;
		upd(l, r, a[x].p[0], lx, mid);
		upd(l, r, a[x].p[1], mid, rx);
		if(a[x].full) a[x].ans = rx - lx;
		else{
			a[x].ans = a[a[x].p[0]].ans + a[a[x].p[1]].ans;
			if(a[x].ans == rx - lx) a[x].full = true;
		}
	}
	ll get(ll l, ll r, ll x = 0, ll lx = 0, ll rx = sz){
		prop(x, lx, rx);
		if(lx >= r || l >= rx) return 0LL;
		if(l <= lx && rx <= r) return a[x].ans;
		ll mid = (lx + rx) / 2;
		ll s1 = get(l, r, a[x].p[0], lx, mid);
		ll s2 = get(l, r, a[x].p[1], mid, rx);
		return s1 + s2;
	}
};
int main() {
	//ios_base::sync_with_stdio(false);
	//cin.tie(nullptr);
	//cout.tie(nullptr);
	ll n, C = 0;
	cin >> n;
	segtree obj;
	obj.init(1e10);
	create();
	for(ll i = 0, code, x, y; i < n; i++){
		cin >> code >> x >> y;
		x += C;
		y += C;
		if(code == 1){
			ll k = obj.get(x, y + 1);
			cout << k << endl;
			C = k;
		}
		else{
			obj.upd(x, y + 1);
		}
	}

  return 0;
}

• Subtask 1: 0 / 100