제출 #1128611

#제출 시각아이디문제언어결과실행 시간메모리
1128611tymoniusz다리 (APIO19_bridges)C++17
73 / 100
3094 ms10156 KiB
#include <bits/stdc++.h> #define pb push_back using namespace std; const int N = 100005; int W[N]; int W_q[N]; int U[N]; int V[N]; bool blocked[N]; bool vis[N]; vector <int> e[N]; int siz[N]; int par[N]; int res[N]; void dfs(int u, int& res) { res += siz[u]; vis[u] = true; for (int v : e[u]) { if (vis[v]) continue; dfs(v, res); } } int find(int a) { if (par[a] == a) return a; return par[a] = find(par[a]); } void unite(int a, int b) { a = find(a); b = find(b); if (a == b) return; par[a] = b; siz[b] += siz[a]; } int main() { cin.tie(0) -> sync_with_stdio(0); int n, m; cin >> n >> m; vector <int> edges; for (int i = 1; i <= m; i++) { int u, v, w; cin >> u >> v >> w; W[i] = w; V[i] = v; U[i] = u; edges.pb(i); } int q; cin >> q; vector <tuple <int, int, int> > queries; vector <tuple <int, int, int> > vec; int root = 100; for (int i = 1; i <= q; i++) { int t, a, b; cin >> t >> a >> b; if (t == 2) queries.pb({b, a, i}); else { vec.pb({a, b, i}); blocked[a] = true; } if (vec.size() != root && i != q) continue; sort(edges.begin(), edges.end(), [](int a, int b) { return W[a] > W[b]; }); edges.pb(0); sort(queries.begin(), queries.end()); for (int i = 1; i <= n; i++) { par[i] = i; siz[i] = 1; } for (int ind : edges) { if (blocked[ind]) continue; while (!queries.empty() && get <0> (queries.back()) > W[ind]) { auto [w_q, s, ind_q] = queries.back(); queries.pop_back(); for (auto [j, w, id] : vec) W_q[j] = W[j]; for (auto [j, w, id] : vec) { if (id < ind_q) W_q[j] = w; } for (auto [j, w, id] : vec) { if (W_q[j] >= w_q) { int u = find(U[j]), v = find(V[j]); e[u].pb(v); e[v].pb(u); } } s = find(s); dfs(s, res[ind_q]); vis[s] = false; for (auto [j, w, id] : vec) { int u = find(U[j]), v = find(V[j]); e[u].clear(); e[v].clear(); vis[u] = false; vis[v] = false; } } unite(U[ind], V[ind]); } for (auto [j, w, id] : vec) { W[j] = w; blocked[j] = false; } vec.clear(); queries.clear(); } for (int i = 1; i <= q; i++) if (res[i] != 0) cout << res[i] << "\n"; return 0; }
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